2 If x and y are positive integers such that x=8y+12,what is the greatest common divisor of x and 1) x=12u,where u is an integer 2) y=12z,where z is 由题知:x=4(2y+3) 由(1)知:x=12u 则y=3k k is an integer.x=12(2k+1) 则x,y最大公因子不能确定. ...
【题目】If x and y are positive integers such that$$ 3 x + 7 y = 1 1 8 $$.Find the maximum value of x-y已知x、y为正整数且$$ 3 x + 7 y = 1 1 8 $$,求$$ x - y $$的最大值. 相关知识点: 二元一次方程(组) 二元一次方程(组)的应用 二元一次方程组的实际应用 二元一...
and 7.We are given that x and y are positive integers such that y is a multiple of 5 and ...
If x and y are positive integers such that x = 8y + 12, what is the greatest common divisor of x and y ? (1)x = 12u, where u is an integer. (2)y = 12z, where z is an integer.A、Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient. B、...
If x and y are positive integers such that x = 8y + 12, what is the greatest common divisor of x and y ? (1)x = 12u, where u is an integer. (2)y = 12z, where z is an integer. 选项: A、Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient. B...
If and are positive integers such that . Find the maximum value of . 已知、为正整数且,求的最大值. 相关知识点: 试题来源: 解析 . 已知,为正整数且, 所以,且与同为奇数或同为偶数, 当,均为奇数时,则,均为奇数, ∴,,, 当时,,符合题意;当时,不是整数,不符合题意; 当时,不是整数,不符合题意...
若x、y和z为正整数使得x2+y2=2xyz,求z的值.If x, y and z are positive integers such that x2+y2=2xyz.
If x and y are positive integers such that y is a multiple of 5 and 3x + 4y = 200, then x must be a multiple of which of the following?_出国考试答疑器_GMAT_试题_Problem Solving
If x, y and z are positive integers such that 27 x + 28y + 29z = 363, find the value of (x + y + z).
1)x=12u=4(2y+3),=> Y=3/2(u-1),X=12u,=> Y/X=u-1/8u,（你看u=3带入x,y.公约为3,=5,公约为6.）x,y正整数 =>公约不定.2）同上理：Y/x=8Z+1/Z 无论z是几,公约都只是1 gmat的题吗,