Ifw=zz−(13)iand|w|=1,then find the locus ofz View Solution Ifω=z/[z−(1/3)i]and|ω|=1, then find the locus of z. View Solution If the roots of the equationx3+Px2+Qx−19=0are each one more that the roots of the equationx3−Ax2+Bx−C=0,whereA,B,C,P,andQ...
If αandβ are roots of the equation x2+px+2=0 and 1αand1β are the roots of the equation 2x2+2qx+1=0, then (α−1α)(β−1β)(α+1β)(β+1α) is equal to : View Solution IF α,β are the roots of the equation 6x2−5x+1=0, then the value of tan−1α+...
百度试题 结果1 题目 If and 3 are the roots of the equation 7. , find the value of a and b. D A) 2 3. b6B) a -3. 6--6C) n 2. 6 5D)a-3.6-2E) None of these 相关知识点: 试题来源: 解析 D 反馈 收藏
If the sum of the roots of the equation x 2 + kx - 3 = 0 is equal to the product of the roots, the value of k is? Solving second order equations Given a generic second-order equation, {eq}ax^2+bx+c=0 {/eq}, its roots can...
let k be a constant,if A and B are the roots of the equation x2 - 3x +k = 0,the A2 + 3B = ?k 是恒数,如果A和B是x 2- 3x+ k= 0的根,A2 + 3B = ? 相关知识点: 试题来源: 解析 因为A和B是x 2 - 3x+ k= 0的两个根,所以A+B=3,即B=3-A将B带入A2 + 3B 原式转化...
百度试题 结果1 题目The roots of the equation x^2+kx+3=0 are real if the value of k is A. 0 B. 2 C. 3 D. 4 相关知识点: 试题来源: 解析 D 反馈 收藏
2SAT2数学题,有关复数1.If i(复数里的那个i)is a root of x4+2x3-3x2+2x-4=0,the product of the real roots isA.-4 B.-2 C.0 D.2 E.42.The nature of the roots of the equation 3x4+4x3+x-1=0isA.3 positive real roots and 1 negative real rootB.3 negative real roots and ...
If both roots of the equation 10x2+px+q=0 are positive integers, find the sum of all possible values of p.设p、q为整数,且p+q=2010.若方程10x2+px+q=0的两根均为正整数,求p所有可能值之和. 答案 −3100.Let α and β be the roots of the equation 10x2+pr+q=0. Then we have...
Let α and β be the roots of the equation x2−2018x+1=0. If βα andαβ are the roots of the equation x2−Sx+1=0, find the value of S. 设方程x2−2018x+1=0的根为α和β.若βα和aβ是方程x2−Sx+1=0的根,求S的值. 相关知识点: 试题来源: 解析 4073322. ...
If the roots of a quadratic equation are A + 1 and A − 1, write the equation in ax + bx + c = 0 form. [ Show all work.] 相关知识点: 试题来源: 解析 x − 2Ax + A − 1 = 0 WORK SHOWN: r + r = 2A = −; rr = A − 1 = ; a = 1, b = −2A, c ...