If the function f(x) = ax^3 + bx^2 + cx + d has a local maximum at x = 1 and a local minimum at x = -1, which of the following must be true? A. a < 0 B. a > 0 C. b = 0 D. c = 0 相关知识点: 试题来源: ...
A. Odd function B. Even function C. Neither odd nor even D. Cannot be determined 相关知识点: 试题来源: 解析 B。若函数 f(-x) = f(x),则函数为偶函数。对于函数 f(x) = x^4 - 2x^2 + 1,f(-x) = (-x)^4 - 2(-x)^2 + 1 = x^4 - 2x^2 + 1 = f(x),所以该...
If f(x) =sin2x+Asinx+Bcosxx3is continuous at x = 0, the value of A,B and f(0) are : View Solution Determinef(0)so that the functionf(x)defined byf(x)=(4x−1)3sinx4log(1+x23)becomes continuous atx=0 View Solution
If the function f (x) = ax3 + bx2 + 11x - 6 satisfies the condition of Rolle's theorem in [1, 3] and f'(2 + 1 ... and 1 (c) 1 and -6 (d) -1 and 1/2
f(x)=x(sin)1x,forx≠0=k,forx=0 is continuous at x = 0, then k = View Solution If f(x)=sinπx5x, ifx≠0=k, ifx=0is continuous at x = 0 , then : k = View Solution If the functionf(x)defined byf(x)={xsin(1x)forx≠0kforx=0is continous atx=0, thenk= ...
If the function f(x) is defined for all real numbers x as the maximum value of 2x + 4 and 12 + 3x,thenfor which one of the following values of x will f(x) actually equal 2x + 4 (A) –4(B) –5(C) –6(D) –7(E) –917.f(x) equals the maximum of 2x + 4 and 12...
If the function f(x) = x³ has an inverse function g(x), then g(8)=? A. 2 B. 3 C. 4 D. 5 相关知识点: 试题来源: 解析 A。因为 f(x) = x³,其反函数 g(x) = ∛x。当 f(x)=8 时,x = 2,所以 g(8)=2。反馈 收藏 ...
The function f(x)=2x+x2 has a local minimum at x = A−2 B0 C1 D2Submit The function f(x)=x2+2x has a local minimum at x=2 (b) x=−2 x=0 (d) x=1 Ax=2 Bx=−2 Cx=0 Dx=1Submit The function f(x)=x3−ax has a local minimum at x=k, where k≥2, then...
If the function f(x) = 2x represents a probability density function, t……【查看更多】 题目列表(包括答案和解析) 给出一个算法: Read x If x≤0 Then f(x)←4x Else f(x)←2x End If Print f(x) 根据以上算法,可求得f(-1)+f(2)=___ 点击展开...
To solve the problem, we need to find the values of a and b for the function f(x)=axebx2 given that it has a maximum at x=2 and f(2)=1. Step 1: Find f(2)We start by substituting x=2 into the function: f(2)=a(2)eb(22)=2ae4b Given that f(2)=1, we have: 2ae4b...