If tanθ+cotθ=2, then sinθ=Solution in Telugu A ±1/2 B 1/√2 C ±1/3 D none Video Solution Text SolutionVerified by Experts The correct Answer is:B | ShareSave Answer Step by step video, text & image solution for If tan theta + cot theta =2 , " then " sin theta = by...
Iftanθ2= t, then the value of1−t21+t2is 09:44 View Solution If x = log (1 + t^(2)) " and " y = t - tan^(-1)t, " then" dy/dx is equal to 02:20 View Solution Doubtnut is No.1 Study App and Learning App with Instant Video Solutions for NCERT Class 6, Class 7...
If {eq}\tan (\theta) = 0.5 {/eq} and {eq}\theta {/eq} is not acute, what are the exact values of {eq}\sin (\theta) {/eq} and {eq}\cos (\theta) {/eq}? Right Triangle Trigonometry: For any right triangle, where {eq}\theta {/eq} is an...
Answer to: If \tan\theta= \frac{1}{5}, what is \cot\theta? By signing up, you'll get thousands of step-by-step solutions to your homework...
Answer to: Find sin(2 theta) if tan( theta) = 2/3 . By signing up, you'll get thousands of step-by-step solutions to your homework questions...
If ( 2 sin 2 theta cos 2 theta 2 ) then find the value of ( theta ) - Given:( 2 sin ^{2} theta-cos ^{2} theta=2 )To do:We have to find the value of ( theta ).Solution: $2 sin ^{2} theta-cos ^{2} theta=2$$Rightarrow 2 sin ^{2} theta-(1-sin...
在C#中,相当于`IF(X AND(2 ^ Y))Then`的语句可以使用位运算符来实现。位运算符是一种操作二进制位的操作符,可以用来执行位级别的操作。在这个例子中,我们可以使用位运算符`&`来实现`...
If cos(θ) = 2/9 and θ is in the first quadrant, find sin(θ). If \sin \theta = \dfrac{\sqrt{77{9} and \theta is in the 2nd quadrant, find the exact value of \cos \theta. Given tan theta = -3 / 5, theta is in Quadrant II, ...
If tan θ = 34 and 0^{\circ }\leq \theta A. \dfrac {3}{5} B. %20" src="https://tiku-data.cdn.bcebos.com/pic/1_8d7e24fcd73ef189514b84214c8c40c9.jpg?auth_key=2357243242-0-0-fcec130a6d88755a223e25944d068d8a" data-width="80" data-height="16" class="exam-img...
(tanHalfTheta, tanHalfTheta, cotHalfTheta, cotHalfTheta)[gl_VertexID]; - if(normalTanValue > 10.0 || normalTanValue < 0.1) return; - - vec2 trapzoidVertexPosition = pos + - offsetSign.x * radius * tangentDirection + - offsetSign.y * radius * normalDirection * normalTanValue; - ...