if ( p || j > i - 1 ) return ERROR单链表插入算法里面的一句, 扫码下载作业帮搜索答疑一搜即得 答案解析 查看更多优质解析解答一 举报 这句话的意思就是只要指针p等于NULL或者j>i-1这两个条件任意一个成立,就返回ERROR 解析看不懂?免费查看同类题视频解析查看解答...
!p是用来判断：插入元素位置大于表长+1。一共n个元素，可以插入新元素的地方为1~n+1，当插入位置大于这个范围的时候，p指针的内容会变成链表最后一项的指针域的内容，即NULL，这时，该判断条件成立。j>i-1的作用：当输入的插入位置小于1时，为非法插入位置。你给的代码当中省略了初始化条件，j的初始...
p等于1(这是true,真)由于 !p是真, j>i是假, 满足 if(!p || j>i) 的条件,所以,执行return ERROR, 函数GetElem()返回ERRORif(!p || j>i) // 第i个元素不存在{ return ERROR;}e=p->data; // 取第i个元素return OK;假设要找第0个元素(结点)...
OpFileSelectionListener::MediaType* media_type = request.extension_filters.Get(i);// extensionsfor(unsignedj =0; j < media_type->file_extensions.GetCount(); j++)RETURN_IF_ERROR(filter.AppendFormat(UNI_L("%s "), media_type->file_extensions.Get(j)->CStr()));// descriptionRETURN_IF_ERR...
if(表达式) { 执行代码块1; } ... else if(表达式m) { 执行代码块m; } ... else } 执行代码块n; } 语义是:依次判断表达式的值,当出现某个值为真时,则执行对应代码块,否则执行代码块n。 注意:当某一条件为真的时候,则不会向下执行该分支结构的其他语句。 分支结构之嵌套if-else语句 C语言中嵌套if...
correctly at every zoom level until I turned them off and on again. This seems new to photoshop 2024, I was not experiencing this on previous years. I will attach the Windows Error reports I could pull, Photoshop did not prompt me to submit a crash report even though I have ...
(!p)||(j>i-1)如果p为真,!p既为假,!是否定 如果j大于i-1则为真,否则为假 ||是"或",两边至少有一个为真时,则表达式为真 如果!p和j>i-1中至少有一个为真,则执行if后面的语句,否则不执行该语句
if(p[i]%2)的意识是：如果p[i]%2=1, 那么就执行if后面的语句；如果p[i]%2=0，那么不执行if后面的语句。因为任何数对2取余数，只能得到0或1，当P[i]为奇数的时候，p[i]%2=1，则执行；当P[i]为偶数的时候，p[i]%2=0，则不执行，而重新判断下一个p[i]。if语句是指编程语言（...
its just incredible its just one of the p its just i dont even its killing me not be its kinda hard with y its like a bad dream its like a lie ive to its like an angel cam its like im looking f its like im looking i its like im not me its magic its me myself and i its...
if she is late she sa if she is playin him if she is stared by o if she wont return th if someone-- and of c if something can go w if statement if that is what i nee if the beard were all if the cloud know if the discussion if the dream is big e if the ielts test for...