python n = 10 if n % 2 == 0: print("n is even") else: print("n is odd") 利用in和not in操作符: 在判断元素是否存在于某个集合时,in和not in操作符可以使代码更加简洁。 python numbers = [1, 2, 3, 4, 5] if 3 in numbers: print("3 is in the list") 使用列表推导式或生成...
int main(){ int n;cin>>n;if(n%2==0){ cout<<"n is odd";}else{ cout<<"n is even";} return 0;} python实现 n=int(input())if n%2==0:print("n is odd")else:print("n is even")
Write a program that accepts a number and prints all even or odd numbers up to that number. Go to: Python Basic Exercises Home ↩ Python Exercises Home ↩ Previous:Write a Python program to get a string which is n (non-negative integer) copies of a given string. Next:Write a Python...
print("Even") if int(input("Enter a number: ")) % 2 == 0 else print("Odd") 二、使用sys模块传递命令行参数 Python的sys模块允许我们通过命令行传递参数,并在脚本中对这些参数进行处理。sys.argv是一个列表,其中包含命令行参数。第一个元素sys.argv[0]是脚本名称,后续元素是传递的参数。例如: import...
if (isEven(number))printf("even\n");elseprintf("odd\n"); CloseHandle(binFile);} 就是这样!现在我们已经具备了判断任何 32 位(32-bit)数字是奇是偶的所有功能,让我们试一试: PS >.\program.exe 300evenPS >.\program.exe 0even...
python numbers = [1, 2, 3, 4, 5] for num in numbers: if num % 2 == 0: print(f"{num} is even") else: print(f"{num} is odd") 5. 示例 for 循环示例: python fruits = ["apple", "banana", "cherry"] for fruit in fruits: ...
n = 100 sum = 0 counter = 1 while counter <= n: # n=100，counter递增，从1递增到101...
1 ... continue ... else: ... print("{} is odd number".format(a)) ... ...
# Python program to check if the input number is odd or even. # A number is even if division by 2 gives a remainder of 0. # If the remainder is 1, it is an odd number. num = int(input("Enter a number: ")) if (num % 2) == 0: print("{0} is Even".format(num)) else...
Another efficient way to check for odd or even numbers in Python is by using the bitwise AND operator (&). This method relies on the fact that the least significant bit of an even number is always 0, while it’s 1 for odd numbers. ...