gmat数学题.if n is a positive integer and n^2 is divisible by 72,then the largest positive integer that must divide n is 答案是24, 答案 72=8*9=2*2*2*3*3若72a=2*2*2*3*3a=n^2所以n最小为2*2*3=12,a=2.相关推荐 1gmat数学题.if n is a positive integer and n^2 is divis...
If n is a positive integer and n2 is divisible by 72, then the largest positive integer that must divide n is A.6B.12C.24D.36E.(E) 48 答案 B暂无解析相关推荐 1If n is a positive integer and n2 is divisible by 72, then the largest positive integer that must divide n is A.6B.12...
百度试题 结果1 题目【题目】If n is a positive integer and n^2+3n-10n^2+6n-16 is a reduced fracnen, thenn^2+3n-10n^2+6n-16= 相关知识点: 试题来源: 解析 【解析】811 反馈 收藏
If n is a positive integer and n2 is divisible by 72, then the largest positive integer that must divide n is A. 6 B. 12 C. 24 D. 36 E. (E) 48 如何将EXCEL生成题库手机刷题 手机使用 分享 反馈 收藏 举报 参考答案: B 复制 纠错 举一反三 病毒性心肌炎的健康宣教无需关注...
If n is a positive integer and n2 is divisible by 72, then the largest positive integer that must divide n is A.6B.12C.24D.36E.(E) 48 点击查看答案 你可能感兴趣的试题 单项选择题 In the preceding figure, if l1∥l2, what is the value of x 点击查看答案 单项选择题 If a = 1 an...
If n is a positive integer,and if the units’digit of the units’digit of 9,the units’digit of . (英汉小词典 units’个位数字) 相关知识点: 试题来源: 解析 5解:个位数为0到9的数的平方的个位数为:;;;由此可知n的个位数是4或6,又的个位数为3,可得n的个位数为4,的个位数为3,的个位数为...
个人看法。理解一下The largest integer that must divide n, 表示的是n一定含有的最大的因子，也就是n取最小值时也一定含有的最大因子。n^2=72x，把72分解，n^2=2^3*3^2*x；n是正整数，那么n^2必然要能开方，也就是说x至少含有一个2，n最小值是不是就是2^2*3=12。12最大的因子就是它本身12...
1If n is a positive integer,and if the units’digit of n2 is 6 and the units’digit of (n-1)2 is 9,the units’digit of (n+1)2 is . (英汉小词典 units’digit:个位数字) 2(5分)If n is a positive integer,and if the units’digit of n2 is 6 and the units’digit of (n...
If n is a positive integer.and if the units’digit of n2 is 6 and the units’digit of (n-1)2 is 9.the units’digit of (n+1)2 is 55. (英汉小词典 units’digit:个位数字)
For convenience, let N represent the product of all integers from 1 through n. Then, since N is divisible by 990, every prime factor of 990 must also be a factor of N. The prime factorization of 990 is 2×32×5×11, and therefore, 11 must be a factor of N. Then, the least pos...