MATLAB Online에서 열기 테마복사 prompt = {'Enter Name: ', 'Enter Age: '}; dlgtitle = 'Input Values'; answer = inputdlg(prompt,dlgtitle); name = answer{1}; % need not to convert to num, it should be a string age = str2num(answer{2}); % proffessor = Issac ...
In MATLAB, "if" is not a function: it is a control statement. We've been nagging MathWorks for years to create a function equivalent to "if", but with no success yet :( Sign in to answer this question. FEATURED DISCUSSION LLMs with MATLAB updated to support the latest OpenAI Models ...
function sigma=julei(A)M=max(A);m=min(A);ave=mean(A);eta(1,:)=M./sum(M);eta(2,:)=ave./sum(ave);eta(3,:)=m./sum(m);sigma(3,3)=0;alpha=0;for i=1:size(A,1) for j=1:size(A,2) if A(i,j)>=ave(j) sigma(i,1)=sigma(i,1)+(A(i,j)...
x = 42;ifexist('myfunction.m','file') && (myfunction(x) >= pi) disp('Expressions are true')end The first part of the expression evaluates to false. Therefore, MATLAB does not need to evaluate the second part of the expression, which would result in an undefined function error. ...
另外，主程序中的alpha和eta也不会自己跑到函数中去，也需要声明成全局变量，或者把定义移到函数中去。其实，你所定义的几个全局变量（以及alpha和eta）在主程序中并没有其他用处，这样的话，不如把这些变量直接在函数中作为局部变量来定义和使用，例如：function sigma=julei(A)M=max(A);m=min(A)...
i want to know if classify function in statistics toolbox in matlab is fisher Linear Discriminant Analysis 댓글 수: 1 Lester Lim2013년 1월 28일 Nope, it depends on which classifier you use, there are many types of classifiers... ...
x = 42; if exist('myfunction.m','file') && (myfunction(x) >= pi) disp('Expressions are true') end The first part of the expression evaluates to false. Therefore, MATLAB does not need to evaluate the second part of the expression, which would result in an undefined function error....
Use the Model Advisor Configuration Editor to define the scope of the analysis by specifying the input parameters.
f是个具有形参函数，你又不给实参，f怎么会有值呢？我看你的意思应该是这样：plot(-4:001:4,f(-4:001:4))另附上运行结果:
'myfunction.m','file') && (myfunction(x) >= pi) disp('Expressions are true') end The first part of the expression evaluates to false. Therefore, MATLAB does not need to evaluate the second part of the expression, which would result in an undefined function error. ...