7}elseif(number<0){ 8printf("The number is negative.\n"); 9}else{ 10printf("The number is zero.\n"); 11} 12return0; 13} In this program, the number is evaluated against three conditions to determine if it is positive, negative, or zero, showcasing how else-if ladders efficiently...
在本练习中,你将使用if、else和else if语句来优化代码中的分支选项并修复逻辑 bug。 使用if 和 else 语句,而不是两个单独的 if 语句 不是执行两项检查来显示消息“你获胜了!”或“抱歉,你失败了”,而是将使用else关键字。 确保Program.cs 代码与以下内容匹配: ...
在编译ifelse时,如果if条件不成立就会跳转到else部分,我们用’branchX’来表示else部分代码分支开始之处,由于编译器在执行ifelse语句时,IfStatementExecutor先会被执行,当它执行时需要知道当前代码是ifelse还是仅仅包含if语句,如果inIfElseStatement设置成true,那表明当前代码是ifelse形式,如果是false表明当前代码是if形式...
In this program, we take a number from the user. We then use theif...else if...elseladder to check whether the number is positive, negative, or zero. If the number is greater than0, the code inside theifblock is executed. If the number is less than0, the code inside theelse if...
C语言实战105例子——实例6用if...else语句解决奖金发放问题,题目:实例解析1.if语句的三种基本形式(1)if(表达式){语句}表达式的值为真时,则执行后面花括号的语句。(当只有一条要执行的语句时,不需要加花括号。)(2)if(表达式){语句l}else{语句2}表达式的值为真时,则
其实,你有没有觉得,jle 和 jmp 指令,有点像程序语言里面的 goto 命令,直接指定了一个特定条件下的跳转位置。虽然我们在用高级语言开发程序的时候反对使用 goto,但是实际在机器指令层面,无论是 if...else... 也好,还是 for/while 也好,都是用和 goto 相同的跳转到特定指令位置的方式来实现的。
}elseif(marks >=60) { cout <<"Grade C"; }elseif(marks >=40) { cout <<"Grade D"; }else{ cout <<"Grade F"; }return0; } Output: Grade B Explanation: The C++ code above illustrates the functioning of an if-else-if ladder statement. The program takes marks of a student as in...
if (x > 10) { if (y > 20) Console.Write("Statement_1"); } else Console.Write("Statement_2"); In this case,Statement_2will be displayed if the condition(x > 10)evaluates tofalse Example 1 In this example, you enter a character from the keyboard and the program checks if the in...
Menu Selection: Interactive menus benefit from “if-else” statements. In a basic calculator program, users can choose an operation by entering a number, and the program responds accordingly: int choice; printf("Select operation:\n1. Addition\n2. Subtraction\n3. Multiplication\n4. Division\n");...
(gain - 200000)*0.05; else if (gain <= 600000) prize = prize4 + (gain - 400000)*0.03; else if (gain <= 1000000) prize = prize6 + (gain - 600000)*0.015; else prize = prize10 + (gain - 1000000)*0.01; printf("The prize is :%d\n", prize); getchar(); system("pause")...