求ax2+bx+c=..求ax2+bx+c=0得实数根,要求:a!=0且b2-4ac>0。求助大佬,百度看了不太懂,可以用if跟else嘛?
百度试题 结果1 题目8. If a,c≠0 and ca,B are the roots of the equationax^2+bx+c=0, then the quadratic equation with 1/α and1/B as itsroots is[J&KKCET] 相关知识点: 试题来源: 解析 +23/(20)÷4/1=6/2=47
百度试题 结果1 题目Pay attention to y=ax^2+bx+c(a≠0), and answer the question.If the two roots of this equation are m&n, which situation can be m0 orm>0, nNote: y=0 (I typed wrong.) 相关知识点: 试题来源: 解析 c/a<0 ...
题目If a great philosopher,and one of the bestselling authors of all time credited the same secret for their success,would you try to follow it too?Here's what Friedrich Nietzsche wrote: "It is only ideas gained from walking that have any worth." And Charles Dickens...
求编程.求方程ax2+bx+c=0的根,用if语句求当b2-4ac>0,等于0和小于0大于0的根并输出结果.实数范围无解时表实数范围无解时表示成复数形式!
用C语言写的,如果追求算法的话要多用几个临时变量,也不是很难的。double delt = b * b - 4 * a * c if (delt > 0){ printf("x1=%lf x2=%lf\n", (-b + sqrt(delt) / 2 / a, (-b - sqrt(delt) / 2 / a);} else if (delt == 0){ printf("x1=x2=%lf\n",...
1.使用 if……else 语句编写程序:完成求解一元二次方程的解,ax2+bx+c=0,考虑以下三种情况:b2-4ac>0 b22.使用 if……else 语句编
If the function f(x) = ax^3 + bx^2 + cx + d has a local maximum at x = 1 and a local
Suppose one of the roots of the equation ax2-bx+c=0 is 2+√3,where a,b and c are rational numbers and a≠0.If b=c3 then |a| equals
Pay attention to y=ax^2+bx+c(a≠0), and answer the question.If the two roots of this equation are m&n, which situation can be m0 orm>0, nNote: y=0 (I typed wrong.)