If A and B are two matrices such that A + B = [{:(3, 8),(11, 6):}] " and " A-B = [{:(5, 2),(-3, -6):}], then find the matrices A and B.
NCERT solutions for CBSE and other state boards is a key requirement for students. Doubtnut helps with homework, doubts and solutions to all the questions. It has helped students get under AIR 100 in NEET & IIT JEE. Get PDF and video solutions of IIT-JEE Mains & Advanced previous year pap...
Suppose that n is an integer. Show that the following three statements are equivalent i) 3n + 4 is even. ii) n + 5 is odd. iii) n^2 is even. by showing (i) \iff (ii) and (ii) \iff (iii). Prove the following for positive integers, a, b, c and n...
Answer to: If A and B are 3 x 3 matrices, det(A) = 2, det(B) = -7. Determine the following values. a. det(AB) b. det(-3A) c. det(A^T) By signing...
As a result, the perception of these behaviors can be a positive or negative indicator of high-quality listening, depending on the speaker’s preferences. Additionally, certain behaviors, such as maintaining eye contact, are often associated with high-quality listening but are unnecessary for it ...
Step 2: Derive IF Decision Matrices by performing pairwise comparison for all criteria: Once the network has been formed, linguistic data is converted into an IF matrix (Abdullah and Najib 2016). The DMs’ opinions are first stated in common language and then converted into the corresponding in...
Let A,B be complex n,n complex matrices such that AB-BA and A commute. We show that, if n=2 then A,B are simultaneously triangularizable and if n>=3 then there exists such a couple A,B such that the pair (A,B) has not property L of Motzkin-Taussky and such that B and C...
An easy exclusion criterion is a matrix that is not nxn. Only a square matrices are invertible (have an inverse). For the matrix to be invertible, the vectors (as columns) must be linearly independent. In other words, you have to check that for an nxn ma
det(A)det(B)=det(AB)=det(I)=1. This implies that the determinants det(A)det(A) and det(B)det(B) are not zero. Hence A,BA,B are invertible matrices: A−1,B−1A−1,B−1 exist.Now we computeI=BB−1=BIB−1=B(AB)B−1=BAI=BA.since AB=II=BB−1=BIB−1=B...
If A and B are square matrices of the same order such that AB=Ba , then prove by inducation thatABn=BnA. Further , prove that(AB)n=AnBnfor alln∈N. View Solution Doubtnut is No.1 Study App and Learning App with Instant Video Solutions for NCERT Class 6, Class 7, Class 8, Class...