are equal. (iii)Two lines perpendicular to the same line are perpendicular to each other. (iv)Two lines parallel to the same line are parallel to each other. (v)If two parallel lines are intersected by a transversal, then the interior angle on the same side of the transversal are equal...
2 True or false.(1)On the same piece of paper,if both the folding line a and the foldingline c are perpendicular to line b,then a //c.……()(2)Two parallel lines do not intersect.…()(3)Passing through a point not on a given line,we can draw infinitelymany lines parallel to ...
百度试题 结果1 题目2)If the lines represented by kx2- 3xy+6y2=0 are perpendicular to each other then A)k=6B)k =-6 C)k =3D)k =-3 相关知识点: 试题来源: 解析 B 反馈 收藏
Answer to: Prove: In a plane, if two lines are parallel to a third line, then the two lines are parallel to each other. By signing up, you'll get...
Cancer stem cells (CSCs) are a subpopulation of cancer cells endowed with high tumorigenic, chemoresistant and metastatic potential. Nongenetic mechanisms of acquired resistance are increasingly being discovered, but molecular insights into the evolutionary process of CSCs are limited. Here, we show that...
If two triangles are similar, the length of their sides are the same. Similar Shapes Two shapes are said to be similar if the ratio of corresponding side lengths is fixed. Congruent shapes are also similar shapes as the ratio of side lengths ...
百度试题 结果1 题目 If the sum of the distance of a point from two perpendicular lines in a plane is then its locusis: A suare) crcle Cstigt line0 two intersecting 相关知识点: 试题来源: 解析 A 反馈 收藏
百度试题 结果1 题目3) Find the value of k if lines represented by kx2+ 4xy- 4y2= 0 are perpendicular to each other. 相关知识点: 试题来源: 解析 k=4 反馈 收藏
No matter what kind of linework you do, always hold your brush perpendicular to the skin. Get the right paint consistency. Getting the right paint consistency will help you obtain vibrant colors and sharp lines. Creamy and inky paint consistencies are what you want for linework. Use creamy ...
Since the legs of a rectangle are perpendicular, the matrix [uv] is orthogonal and so we even have a simple formula for the inverse: [uv]−1=[uT/||u||2vT/||v||2]. If you want to check many points for the same rectangle, this matrix can be easily precomputed and stored, so ...