aux1aux2IIPaux3PixelsEOFclktreadytvalidtlasttuser[1]tuser[0]tdata KLUv/QBYpCgFetpbhy7ArmZUbNcdjc7V3voelYK+vmADV+k8S1Ad3U/AbMktubLb40RVVjEJgpAj CHIQXQqBB5UHQ/gvKtJn6XtpFotGrVlftDSdJLNZ1MxJ32ZtohpCylkH7hSSGo24lONdncPScZXH aEuDNtkgrtcGXTd4Na//G+P96Dg+u3tNGrfsO0ZESEAovGO4N2m9...
src_reqdst_acksrc_clkBus Synchronizersrc_sig [DATA_WIDTH-1:0]dst_sig [DATA_WIDTH-1:0]dst_clksrc_sync_reqdst_sync_ack KLUv/QBYzCIFutCjhCvQsFBqAOsjIXvXILs/c0foD0AVXXt2D5bxK6R02S0isZZoL0e8/PxqfFwT ZwpDB10HZmsHjfqkkPGXVGlyeM73TpdsW5WxjZexyZS4Y7O0DxgrfsEmObOcRNIJuW/n9RLsi194 fX...
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=2,然后求出MD=2AM=4EM,判断出④正确,设正方形ABCD的边长为2a,利用勾股定理列式求出AF,再根据相似三角形对应边成比例求出AM,然后求出MF,消掉a即可得到AM= 2 3 MF,判断出⑤正确;过点M作MN⊥AB于N,求出MN、NB,然后利用勾股定理列式求出BM,过点M作GH∥AB,过点O作OK⊥GH于K,然后求出OK、MK,再利...
【题目】如图,已知E、F分别为正方形ABCD的边AB,BC的中点,AF与DE交于点M,O为BD的中点,则下列结论:①∠AME=90°;②∠BAF=∠EDB;③∠BMO=90°;④MD=2AM=4EM;⑤AM=MF.其中正确结论的个数是( ) A.5个B.4个C.3个D.2个 试题答案 在线课程 ...
6746VxuDfp8Xl3T3ELHFJZknVXg4ZYNXvrONXb2W5iafmF11NZI c4cusc5bZTpra4WWpaiza2pri9Odak0p1HWLOrZIO/f2UyeNtlXXSbM+383abnW8MWPZeJxyuUw3 Pi/O+9lbXM4S7mXinG9Hz/W7BektCI9GD/Xmfr855y027yYL89LOZg9e1eBdY/sWg6eWQ4incN74 8M6+hDp3i725S9up0tndnG5v6Lam7o7mrss6/cLC7qFk5pIhHgJgNv34Usd0X...
fbMHP4gxo8IuDNOfQ2mWIZcNESFscCVI7uTCY8ib3Dscc6lKn3cWxGz+awcG3YfcSv1CGLNuoMF6 a2EI/vUV9A2fSJfZNvS4L/24MkKrUSB194JEX4OR+jdZwqowmEp2L2kcIsUK1KuB3PtCdEE8FsbT mi+z/fLsnXwr+qSbxPA4OTy4i0YwcNS057UX45bfSlF233prgwayhXvb65hC3q8/cqaAEev4yJnI pl9UWTl6VJ0o/FRiN3+0zULMyYl7w0ycRz...
如图.已知E.F分别为正方形ABCD的边AB.BC的中点.AF与DE交于点M.O为BD的中点.则下列结论:①∠AME=90°,②∠BAF=∠EDB,③∠BMO=90°,④MD=2AM=4EM,⑤AM=MF.其中正确结论的个数是( )A.5个 B.4个 C.3个 D.2个
【题目】如图,已知E、F分别为正方形ABCD的边AB,BC的中点,AF与DE交于点M,O为BD的中点,则下列结论:①∠AME=90°;②∠BAF=∠EDB;③∠BMO=90°;④MD=2AM=4EM;⑤AM=MF.其中正确结论的个数是( ) A.5个B.4个C.3个D.2个 试题答案 在线课程 ...
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