The stoichiometric mole ratio of C2H5OH, NaOH and I2 for a maximum theoretical yield is 1:2:4, which will yield CHI3, NaI and H2O in a ratio of 1:2:4. If you combine 46.068g (or 1 moles) of C2H5OH (molar mass = 46.068 g/mol), 79.994g (or 2 moles) of NaOH ...
Na2CO3 Molar Mass Na2CO3 Oxidation Number Ethanol - C2H5OH Ethyl Alcohol Lux Dehydrated Ethanol 1-Hydroxyethane Spiritus Vini Methylcarbinol Hydroxyethane Alcohol (Ethyl) C2H5OH Molar Mass C2H5OH Oxidation Number Products Water - H2O Hydroxic Acid H₂O [Oh2]...
a. The limiting reactant is the one with the higher molar mass. b. A is the limiting reactant because you need 6 moles of Balance the reaction: CH4 + O2 arrow CO2 + H2O a. If 1 mole of CH4 and 1.5 moles of ...
Which will have the greater entropy: 2 moles of H2(g) + 1 mole of O2(g) or 2 moles of H2O(g)? Explain. How does the standard entropy of a substance depend on its molar mass? Which of the following list below has the lowest entropy? Explain your answer. a)...
aC6H8O6+bI3=cC6H6O6+dI +fH Step 2: Create a System of Equations Create an equation for each element (C, H, O, I) where each term represents the number of atoms of the element in each reactant or product. C:6a +0b=6c +0d+0fH:8a +0b=6c +0d+1fO:6a +0b...
Step 2: Create a System of Equations Create an equation for each element (C, H, I) where each term represents the number of atoms of the element in each reactant or product. C:3a +0b=3cH:6a +1b =7cI:0a+1b =1c Step 3: Solve For All Variables ...
Effect of temperature on product selectivity and C2H5OH conversion over M/CeO2 catalysts. RFReiegaacuctrtiieoon6n .ccEoofnnfdedciitttiiooofnntsse:: mSS/p/CeC r=a =3tu,3 rm,emcoatcn a=tp 2=r5o20d 5mu0cgmt,s gFe,Tle F=cT...
b = 2 (C6H9I2NO) c = 9 (H2O) d = 12 (CO2) f = 31 (NaCl) g = 2 (I2) h = 2 (N) Step 4: Substitute Coefficients and Verify Result Count the number of atoms of each element on each side of the equation and verify that all elements and electro...
g = 6 (C2H5OH) h = 9 (I2) Step 4: Substitute Coefficients and Verify Result Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced. ...
The stoichiometric mole ratio of NaNO2, KI and H2SO4 for a maximum theoretical yield is 2:2:2, which will yield I2, K2SO4, H2O, Na2SO4 and NO in a ratio of 2:2:2:1:1. If you combine68.995g (or1moles) ofNaNO2(molar mass = 68.995 g/mol...