or .DCVOLT V(node1) = val1 V(node2) = val2 ... 例子: .IC V(11)=5 V(4)=-5 V(2)=2.2 .DCVOLT 11 5 4 -5 2 2.2 上面两条声明是等效的。 .nodeset 声明用来设定节点电压初始值。语法: .NODESET V(node1)=val1 V(node2)=val2 ... or .NODESET node1 val1 node2 val2 ...
the.NODESETstatement(not.IC)forinitialization,toavoidDC convergenceproblems. Forthesyntaxofthe.PZ(Pole/Zero)statement,seetheHSPICE CommandReference. Pole/ZeroAnalysiamples Thefollowingareexamplesofdifferenttypesofpole/zeroanalysis. Example1–LossFilter ThefollowingisaHSPICEinputfile,forafifth-orderloss prototy...
.NODESET/.IC ? Provide initial node voltage information for Hspice to calculate bias point ? Initial conditions and/or nodesets –.IC v(node1)=value v(node2)=value ... – .NODESET v(node1)=value v(node2)=value … ? Which nodes? –Observe the nonconvergent diagnostic table in the ...
HSPICEGuide
大学-HSPICE使用教程 SPICEOverviewCircuitSimulationBackground 大学-HSPICE使用教程 SPICEBackground SPICEOverview SimulationProgramwithIntegratedCircuitEmphasis DevelopedbyUniversityofCalifornia/Berkeley,1972Simulationinsteady-state,transient,andfrequencydomainsWidelyadopted,becomedefactostandard SBTSPICE,HSPICE,Spectre,TSPICE,...
.NODESET/.IC ? Provide initial node voltage information for Hspice to calculate bias point ? Initial conditions and/or nodesets – .IC v(node1)=value v(node2)=value ... – .NODESET v(node1)=value v(node2)=value … ? Which nodes? – Observe the nonconvergent diagnostic table in ...
Synopsys的Hspice入门
直流分析:最直接的应用是取得CMOS转移特性曲线;瞬态分析:用于数字标准电路元的时间特性分析,如响应波形的上升、下降与传递延迟时间等;零点/极点与交流分析:常用于放大器与滤波器的特性评估。进阶分析,则包含噪声与失真分析(noise/distortionanalysis)、蒙特卡罗与最坏情况分析(MonteCarloandWorstCase...
(2 2 100KHz ) .op .tran .1u 10u *.plot tran V(2) V(1) .probe .opti on list node post *model .MODEL MOSN NMOS VTO=0.7 KP=110U +LAMBDA=0.04 GAMMA=0.4 PHI=0.7 .MODEL MOSP PMOS VTO=-0.7 KP=50U +LAMBDA=0.05 GAMMA=0.57 PHI=0.8 .end 大信号瞬态仿真结果: GraphO t⑹改为小...
(OPA) unity-gain freq, phase margin, DC gain bandwidth, quality factor HSPICE Demo Oscillator for example .option list node nomod .ic V(1)=5 .global VDD .param Lm=0.5u Wn=0.7u Wp=1.2u .tran 0.1n 5n Vdd VDD 0 5 .subckt inverter in out Mp out in VDD VDD mod2 W=Wp L=Lm Mn...