Is there a way to use aic/bic for the models defined by the user (e.g,, y1= ax+bx^2+c, y2=ax+dx^3+sin(x))? Many thanks in advance! 댓글 수: 0 댓글을 달려면 로그인하십시오. 이 질
Or use the fact that cos(t/2) == sin(t/2 + pi/2) So we can use theSine Waveblock with parameters: Amplitude = -2 Frequency = 1/2 Phase = pi/2 Bias = 2 댓글 수: 0 댓글을 달려면 로그인하십시오. ...
If your hardware supports it, turn on the TMU support (--tmu_support=tmu0 and --fp_mode=relaxed) in addition to FPU support (--fpu_support=fpu32) and then call the sin(), cos()- what the compiler does in this case is replace those calls with TMU instr...
Ouvrir dans MATLAB Online Use linspace and meshgrid to create regular mesh ThemeCopy xx = linspace(min(xdata),max(xdata),20); yy = linspace(min(ydata),max(ydata),20); [X,Y] = meshgrid(xx,yy); Use griddata to calculate value at each grid point ThemeCopy Z = griddata(xdata,ydata...
how to use fzero?f=@(b) tan(t)-2*cot(b)*(((m1^2)*(sin(b))^2)-1)/((m1^2*(y+cos(2*b)))+2));
Sign in to comment.More Answers (7) N Narayan rao on 25 Sep 2016 Vote 6 Link Edited: Walter Roberson on 15 Jul 2017 Open in MATLAB Online ThemeCopy x = -3:0.1:3; y1 = sin(x); y2 = cos(x); y3= tan(x); y4=1./cos(x); figure subplot(2,2,1) plot(x,y1) ...
Open in MATLAB Online I am having difficulty in finding a high-resolution frequency spectrum even though I have a pretty large number of time domain data samples (1999999 data points). The fundamental frequency peak in FFT is with a resolution of 50 Hz when I use fft(). I had...
MATLABand/or your computer. Errorin eyescript What should i do to prevent this error from happening? Thanks in advance. ThemeCopy Maximumrecursion limit of 500 reached. Use set(0,'RecursionLimit',N) to change the limit. Be awarethat exceeding your available stack space can crash MATL...
I think it can be done much more elegant by performing a FFT at a single frequency, in this case "fl". But I have to think about it and if I get a solution I will come back later.The
MATLAB Online에서 열기 This solution relies on only one for-loop (although technically you could replace this for-loop, too). 'sumOut' is the solution to the equation. kMax = 10; out = zeros(1,kMax); fork = 1:kMax out(k) = sum(sin((pi + 0.1)./(1:k)) .* exp(-k/...