https://leetcode.com/problems/max-consecutive-ones/ Last edited: Jan 30, 2017 Jan 30, 2017 #6 FallenApple 564 61 So here is what I ended up with. It turned out to be a problem with the range. Python: A=[0,1,1,1,0,0,1,1,0,0,0,1,1,1,1] #needs 0 at the end...
Repository files navigation README this contains all the institution an approaches to solve a problem on leetcode platforms About cotaining all codes int java ,how i solve a particular problem Resources Readme Activity Stars 1 star Watchers 1 watching Forks 0 forks Report repository Re...
Let’s try to code withRecursion. See code below: Now, whenever you are able to find a recursion solution then please try to do it withmemoization technique. It reduces the time complexity. So basically in this, we store the calculated result in an array and if we...
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https://leetcode-cn.com/problems/how-many-numbers-are-smaller-than-the-current-number/solution/liang-chong-fang-fa-pai-xu-ying-she-you-xiao-gai-j/ class Solution { public int[] smallerNumbersThanCurrent(int[] nums) { if(nums==null||nums.length<2) return new int[]{0}; in...
1365. 有多少小于当前数字的数字 - 给你一个数组 nums,对于其中每个元素 nums[i],请你统计数组中比它小的所有数字的数目。 换而言之,对于每个 nums[i] 你必须计算出有效的 j 的数量,其中 j 满足 j != i 且 nums[j] < nums[i] 。 以数组形式返回答案。 示例 1:
Create 1423. Maximum Points You Can Obtain from Cards.java Jan 24, 2025 README.md Update README.md Dec 28, 2024 Repository files navigation README this contains all the institution an approaches to solve a problem on leetcode platforms ...