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Example Implementation:Consider the problem of checking if a string is a palindrome using mutual recursion in Python: def isPalindrome(s): if len(s) <= 1: return True elif s[0] == s[-1]: return isPalindrome(s[1:-1]) else: return Falsedef checkPalindrome(s): return isPalindrome(s...
print("\n\n--- Let's find out if number is Prime or not --- \n" + "Enter Number: "); Scanner myInput = new Scanner(System.in); System.out.println(crunchifyIsPrimeNumber(myInput.nextInt())); // Java Program to display first n prime numbers crunchifyPrintFirstNPrimeNumbe...
import java.util.*; public class Main { public static void main(String[] args) { Scanner s = new Scanner(System.in); System.out.print("Enter a number:"); int n=s.nextInt(); for(int i=1; i <= 10; i++) { System.out.println(n+" * "+i+" = "+n*i); } } } Copy Ou...
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Print the reverse of a string that contains digits in Python Convert a String to camelCase in Python Capitalizes the first letter of each word in a string in Python Python program to check if a string is palindrome or not Python program to input a string and find total number uppercase ...
Check Palindrome in Python Using List Slicing Example # Enter stringword=input()# Check for palindrome strings using list slicingifstr(word)==str(word)[::-1]:print("Palindrome")else:print("Not Palindrome") The program begins by prompting the user to input a string using theinput()function...
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so you need check all of them. Calculate primes up to sqrt(10^14), factorise N using them and recursively build all divisors, check them for correctness. Then solve case with length >= 4. It is easy to prove B in that case is < N^(1/3), so you can check all B up to it. ...