If you want to use query vars in your PHP functions you can use WordPress’ get_query_var function.<?php $url_parts = parse_url( home_url() ); $current_url_with_query_string = $url_parts['scheme'] . "://" . $url_parts['host'] . add_query_arg( NULL, NULL ); echo $...
@vsemozhetbyt Yes, I am trying to get the URL of the new page when the user clicks the new page it should take the new page screenshots. Himly1 commented Jan 19, 2023 @samimhakimi Sorry, I cannot reproduce, I get about:blank in the console, it is the URL of a new empty page....
Current URL: {{ request.get_full_path }} This code will output the complete URL for the current page. Accessing Specific URL Components If you need to access specific components of the URL, such as the path, query parameters, or the domain, you can use the following attributes: : The p...
Hi all, some weeks ago, the App-Info Menu changed. Back then there was easy option to copy the current URL. e.g. when browsing through my Jira Web...
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Let’s look at a few methods of making it happen. But first, you might be wondering why on earth we’d even want to do something like this. Why you might need the current URL So before we get into thehow, let’s first answer the bigger question: Why would you want to get the ...
Steps to get current route URL in Angular. 1. Import Router,NavigationEnd from angular/router and inject in the constructor. 2. Subscribe to the NavigationEnd event of the router.3. Get the current route Url by accessing NavigationEnd url property.
In this post, I am going to share the information How To Get Current Page URL from Apex code in Salesforce. So we need to use Apexpages.currentPage() methods. Get Current Page URL ‘getHeaders()’ : It return a map of the request headers.where the key string contains the name of ...
public with sharing class pageurlclass{ public String headerdata{get;set;} public string urlvalue{get;set;} public string url{get;set;} public pageurlclass(){ headerdata= ApexPages.currentPage().getHeaders().get('Host'); urlvalue=Apexpages.currentPage().getUrl(); url='https://' + ...
@FreugdFredThat means that page.url is already a string, and is not a function ( although not only functions are callable) that you can execute/ call. If you also look at thedocs, you’ll see thatpage.urlreturns a string. So to fix your problem, just remove the parenthesis. ...