Having a quadratic equation to solve, several steps must be followed in order to find its roots (x-intercepts): Rearrange our equation in a form ax2+bx+c=0 Factor it out if possible into a form a(x−x1)(x−x2), then our roots are x1 and x_2 ...
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One way on how to find the vertex and the intercepts of a quadratic function is by graphing. In this method, we can visually see the important points of the graph. However, we can also solve the following algebraically. Answer and Explanation:1 ...
Since we are not interested in other covariates, we omit them and describe this model algebraically as $$ {\displaystyle \begin{array}{c}{y}_{ij}\sim \mathrm{Binomial}\left(1,{\pi}_{ij}\right)\\ {}\mathrm{logit}\left({\pi}_{ij}\right)=\log \left(\frac{\pi_{ij}}{1-{\pi...
@Carolyn: I'm not quite sure what your question means (don't want to lead you astray!). If we have a y-intercept, the we find it by substituting x = 0. Nothing magic about it - when x does equal zero, we are on the y-axis.John...
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The zeroes of a function can be determined either algebraically or graphically. In this problem, we will use the graphical method. In the graphical method, we just need to find the point where the graph intersects the x-axis.Answer and Explanation: ...
How do you graph f(x) = -x^2 + 2x + 5 and identify the x-intercepts and vertex? The graph of the function f(x) =ax^2+bx+ c has its vertex at (0, 1) and passes through the point (1, 5). Find a, b, and c. How to find the vertex connectivity of...