Hi, I am very new to matlab and I am trying to solve an equation with an infinite serie. The equation looks like this: The variable is \alpha and the rest are all parameters.So this thing looks ugly, and almost clearely it has no closed form solution, ...
Warning: Matrix is singular to working precision. ans =5×1 NaN NaN Inf Inf Inf If you do not have actual infinite entries then thereisn't"one equation" that makes it "not have a solution". Consider for example [1 2 3 2 4 6 ...
How to find all posible solutions for a1,a2,a3,a4,b1,b2,b3,c1,c2 >0 ? ThemeCopy solution 1: ... solution 2: ... ... solution n: ... Matrix B are changing with coefficients of geometric progression, 1,25 in this case Thanks1 Comment...
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Example 1: Find the points of maxima and minima of a function: y = 2x3 –3x2 + 6 Solution Given function: y = 2x3 –3x2 + 6 Using the second order derivative test to find a function’s maximum and minimum: Taking the first derivative of: y = 2x3 –3x2 + 6 —– (eq 1) ...
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