exp(i*theta) = cos(theta) + i*sin(theta) to solve for gammaL. Both solutions should be equally valid, just expressed differently. For example: e = 1; thetaC = 2; vpa(subs(sol.gammaL),5) ans = symsK vpa(atan(-thetaC/e)) + K*pi ...
If v x w = (-4,-3,-5) and v. w = 2, find tan(theta), where theta is the angle between v and w. Solve the equation. tan theta = 2 sin theta Solve equation square root of {3 tan(\theta) + 1} = 0, where \theta belongs to (0, 360). A. 210 and 330 ...
It is best to vectorize your function using element-wise operations, then create it as a function of the two variables, then use integral2 to numerically integrate it: m = 3; n = 5; p = 7; f = @(theta,phi) m*p*cos(theta).^3.*sin(phi).^2 - n*p*cos(phi).^2.*cos(theta...
How to find the derivative of a function? How do you find the derivative of the function : 4t^2-6t+10? 1. Find the derivative of y = xe^{5x} 2. Find the derivative of s(x) = 45(3x^3 - 8)^{3/2} A) Find the derivative of f(x) = x*sin^(-1)x. B) Find...
a)\int_{0}^{2}\frac{\log _{2}(x+2)}{x+2}dx b)\int_{\ln 4}^{\ln 9}e^{x/2}dx Find the derivative of y with respect to t.y=2^{\sin 3t} 1. Evaluate the integral. \int_{-\frac{\pi}{4^{\frac{3\pi}{48\sec \theta \tan \theta d\theta \\ a. -8\sqrt{2}...
What is the value of the sin 15? opposite to the angle to the length of the hypotenuse in a right triangle. To find the sine of 15 degrees, we can draw a right triangle with one of the angles as 15 degrees. Using basic trigonometric ratios, sine theta = opposite side/hypotenuse. For...
I can't take responsibility for incorrect and misleading information you may find out on the internet. All Photoshop number calculations use the open document color space first, and if that doesn't apply, it goes to your working spaces. All RGB numbers refer to a specific co...
theta = (0:n-1)'/n*2*pi; x = 3*(cos(theta)+1); y = sin(theta)+1; %% circle fit % let's assume we want to fit a circle to the front portion (leading edge) ind = x<0.1; % circle fit here then plot par = CircleFitByTaubin([x(ind) y(ind)]); % Ou...
sin 4530^@ = sin(25pi+pi/6) = sin(2**12pi+pi+pi/6) =sin(pi+pi/6) = sin210^@ So, 180^@ lt 210^@ lt 270^@. :. theta lies in 3rd quadrant.
y = sin(theta)*x0 + cos(theta)*y0 + yc; plot(x,y,'k--') end To this example, you will obtain a figure which validates this method. Thank you so much Wan. Your suggestion did solved my problem. Once again, many thanks