1. Find mole of H2, N2 and NH3 after equilibrium 2. Calculate the heat. Given that delta H = -91 kJ 3. Calculate K my solution : 3H2 + N2 ---> 2NH3 I 3 9 C -3x -x +2x E 3-3x 9-x 2x then 2x/(2x+12−3x−x) = 1/2 then x = 2 but it's impossible because ...
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In this article, we'll explore what makes tunnels such an attractive solution for railways, roadways, public utilities and telecommunications. We'll look at the defining characteristics of tunnels and examine how tunnels are built. We'll also look at the "Big Dig" in detail to understand the ...
a mathematical formula involving the initial concentrations of the two solutions, as well as the volume of the final solution, allows you to work out the final concentration in percent of the volume of the new combined solution.
How many grams of water are required to dissolve 27.8 g of NH4(NO3) (MM = 80.05 g/mol) to make a 0.500 M solution? Dissolution: Dissolution (or dissolving) is a process of incorporating a solid into a liquid solution. In the process,...
Parts of Solutions In order to correctly express units of solubility, it is necessary to understand the terminology used to describe a solution. A solution is made of two parts: the solute and the solvent. The solute is the substance that is being dissolved, while the solvent is the substanc...
Mole depicts a sample's quantity. It is calculated by dividing the sample's mass by its molar mass. It is also calculated from the molarity formula with known values of concentration and volume.Answer and Explanation: Given: Volume of the solution is 2.50 L Molarity of t...
The pressure of a gas over a soluiton in which the gas is dissolved is proportional to the mole fraction of the gas dissolved in the solution i.e., p prop x p = K(B) (where K(H) is Henry.s is Henry.s law constant).
We find that the Mg content of the oxide layer decreases from 33 at.% in the solution heat treated state to 15 at.% in the peak-aged sample. Through the use of deuterium (D) we reveal the presence of D (i.e. H) in the electrochemically grown oxide from water splitting, ...
Subpopulations of soluble, misfolded proteins can bypass chaperones within cells. The extent of this phenomenon and how it happens at the molecular level are unknown. Through a meta-analysis of the experimental literature we find that in all quantitative