cos(2θ)=-cos(4θ) There are 2 steps to solve this one. Solution Share Step 1 Answer: Explanation: To solve the equation (cos(2θ)=−cos(4θ)), we'll use trigonometric identities. First, we'll use the double angle ...View the full answer Step 2 Unlock Answer...
exp(i*theta) = cos(theta) + i*sin(theta) to solve for gammaL. Both solutions should be equally valid, just expressed differently. For example: e = 1; thetaC = 2; vpa(subs(sol.gammaL),5) ans = symsK vpa(atan(-thetaC/e)) + K*pi ...
Find the area between the circles x^2 + y^2 = 2 and (x - 1)^2 + y^2 = 1. Find the area inside the circle r = -8sin(theta) and outside the circle r = 4. What is the formula to find the area of a circle? Let A be the area of a circle with radius r. If {dr} ...
Step 2: Use definitions to find the remaining trigonometric functions. {eq}\sin(\theta) = -\frac{9}{\sqrt{130}} {/eq} {eq}\cos(\theta) = -\frac{7}{\sqrt{130}} {/eq} {eq}\csc(\theta) = -\frac{\sqrt{130}}{9} {/eq} {eq}\sec(\theta) = -\frac{\sqr...
theta = linspace(0,pi/2) %calculate the pressure p = pm + pA*(cos(omega*t)); %calculate the displacement zeta = (pA/dA*a)*cos((omega*t)-(pi/2-theta)); The problem is I need to find the omega(angular frequency) and theta but Im using the 'linspace' function댓...
$$c^2=a^2+b^2-2ab\cos(\theta) $$ Answer and Explanation:1 To find the length of a parallelogram, we need the length of the corresponding sides of the diagonal and the angle formed by the corresponding sides. ... Learn more about this topic: ...
How to find exact value of sin 18°? Let A = 18° Therefore, 5A = 90° ⇒ 2A + 3A = 90˚ ⇒ 2θ = 90˚ - 3A. Taking sine on both sides, we get. sin 2A = sin (90˚ - 3A) = cos 3A. ⇒ 2 sin A cos A = 4 cos^3 A - 3 cos A. ...
How to Find Trigonometric Ratios Given a Right Triangle: Example 1 Given the right triangle depicted below, calculate all six of the trigonometric ratios of {eq}\theta {/eq}. Step 1: Identify the sides of the right triangle and their lengths. ...
What maximum angle will the pendulum swing to if the effective radius of the pendulum is 28cm? Homework Equations How to find theta? The Attempt at a Solution I converted 28cm to 0.28m; 10g to 0.010kg; and 280g to 0.280kg. I used the equation 1/2mv^2 = mgh to fin...
d6= 1/3*m2*L2^2; f1 = (0.5*m1 + m2)*L1*g; f2 = 0.5*m2*L2*g; symsTheta0 Theta1 Theta2; symsDTheta0 DTheta1 DTheta2; x_ = transpose([Theta0 Theta1 Theta2 DTheta0 DTheta1 DTheta2]); D(x_)= [d1 d2*cos(x_(2)) d3*cos(x_(3)); ...