Connect and share knowledge within a single location that is structured and easy to search. Learn more about Teams How do I find general solutions to trig equations with multiple different trig functions [duplicate] Ask Question Asked 9 days ago Modified 9 days ago Vie...
If I try to integrate these like in integral calculus, the two terms on the left-hand side look a lot more reasonable (the integral of 1/(x+2)dx=ln(x+2)+C) than the gigantic term on the right-hand side. In fact, if you gave me (4x+5)/(x^2 + x-2) and told me t...
Trig functions are equations containing the trigonometric operators sine, cosine and tangent, or their reciprocals cosecant, secant and tangent. The solutions to trigonometric functions are the degree values that make the equation true. For example, the equation sin x + 1 = cos x has the solutio...
Solve more complex equations in the same manner. For example, (48x^2 + 4x -70)/(6x -7) = 90. The first goal is to isolate the variable. This requires simplifying the left hand side of the equation. Factor the numerator and denominator of the equation completely. In this equation, th...
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Clearly, this equation needs to be solved fory'in order to determine howy'is related toxandy. Isolate all terms withy'on one side: y' - xy'cos(xy) = ycos(xy). Then factor out they'to get: y'(1 - xcos(xy)) = ycos(xy). ...
In Section 3 we show how to factor x4+10x2−96x−71 into two quadratic polynomials with real coefficients. Then, in Section 4 we find real constants a and b such that the change of variable given by x=at+bt+1 allows us to rewrite each of the quadratic polynomials in x as (t+1...
sin x (2 cos x - 1) = 0 factor out sin x By Zero Product Rule sin x = 0, i.e., x = kπ where k is any integer Or 2 cos x - 1 = 0 2 cos x = 1 add 1 to both sides cos x = 1/2 x = π/6 + 2kπ where k is any integer or x = 5π/6 + 2kπ where ...
The additive inverse is a specific number, and every real number has one! That is, these inverses occur in pairs. We'll look at what their properties are, how to find them, and the most common applications. Explore our homework questions and answers library ...