spring constantnumerical calculation methodBased on the Winkler's hypothesis, this paper discusses how to determine the spring constant of groundwork in design of underground structure. When no sufficient experimental conditions are available, the method of numerical calculation can be used to determine ...
When you compress or extend a spring, it exerts a force opposite the force you exert in an effort to return to its equilibrium position. The amount of force is characteristic of the spring and is represented by the spring constant,k. According toHooke's law, the relationship between extensio...
When a spring stays within its elastic limit and obeys Hooke’s law, the spring is called an ideal spring. How to find the spring constant (example problem) Suppose that a group of car designers knocks on your door and asks whether you can help design a suspension system. “...
A spring has a spring constant of 50 N/m. How much force is needed to stretch the spring by 2 meters? A. 100 N B. 80 N C. 120 N D. 150 N 相关知识点: 试题来源: 解析 A。解析:Force = spring constant×displacement. 50 N/m×2 m = 100 N. Option B, C and D are ...
A spring has a spring constant of 50 N/m. How much force is required to stretch the spring by 2 m? A. 100 N B. 110 N C. 120 N D. 130 N 相关知识点: 试题来源: 解析 A。Force = Spring constant×displacement = 50×2 = 100 N. Option B, C and D are incorrect....
Step 2:Calculate the effective spring constant for all springs in parallel using the equation: {eq}k_{eff}=k_1+k_2+...+k_i {/eq}. How do Springs Behave in Parallel? Springs in Parallel:When multiple springs are individually attached from one object to another they ...
The helical molecule acts as a spring and compresses .4% upon becoming charged. The Coulomb constant is 8.99 X 109 N*m2/C2. Determine the effective spring constant of the molecule. Take into account the compressed length when calculating the distance between the ends of the molecule...
弹簧的力常数为150牛/Cm,a,将弹簧从原位置拉60毫米需要多大的功 F*S=900J B再拉7.6毫米需要再做多少功=114J 算的不知道对不对哈 ，数学好久没学了哈哈
To determine the acceleration of a spring-mass system we use a=kxm where a is acceleration in meters per second squared, k is the spring constant in Newtons per meter, x is the displacement from equilibrium of the spring in meters, and m is the mass of the object in kilograms...
The addition of a small amount of fluid to a suspension may dramatically change the macroscopic properties of the material, and attractive capillary forces between two grains deforms the grains elastically, yielding a ''spring constant'' for further deformation9. Along the same lines, just a ...