The program below shows how we can use thejson_decode()function to extract data from a JSON string. <?php$jsonString='{"firstName":"Olivia","lastName":"Mason","dateOfBirth":{"year":"1999","month":"06","day":"19"}}';$data=json_decode($jsonString);echo("The data is: \n")...
TheWarning "json_encode() expects parameter 2 to be long, string given" happens usually because you're providing instead of the number of a constant, a string as second argument for json_encode. This happens normally because you're using an inexistent constant as seco...
<?php $str = "Héllo, Wörld!"; echo json_encode($str, JSON_UNESCAPED_UNICODE); ?> #output: "Héllo, Wörld!" How to decode JSON string into PHP object? To decode a JSON string back into a PHP object, you can use the json_decode() function. The result object can be any PHP...
<?php $Json = file_get_contents("myfile.json"); // Converts to an array $myarray = json_decode($Json, true); var_dump($myarray); // prints array ?> Output: array(3) { [0]=> array(3) { ["id"]=> string(2) "01" ["name"]=> string(12) "Olivia Mason" ["designation...
To parse JSON with PHP we will be using the funcionjson_decode, this function takes a json string for its first parameter and an optional boolean (true/false) for its second parameter. The second parameter, if set to true, returns the json string as an associative array, if it’s not...
( $data->jsonSerialize(), // convert collection to array 'root', // root element name true, // replace spaces by underscore in element's names 'UTF-8' // encoding ); // should send $result to view, I kept the variable name return response($result)->view('xml', ['data' => ...
Using data from JSON with PHP First, to drill in that JSON is simply a string, we're going to write JSON into a PHP string and apply it to a variable called $data. $data = '{ "name": "Aragorn", "race": "Human" }'; Then we'll use the json_decode() function to convert the...
JSONDecoder().decode(TopLevel.self, from: data) print(decoded?.name)``` Boost Copy aamirkhan question OOPer Jul ’20 Is this the right structure of your JSON as referred in my comment of another thread of yours?You should better leave some replies to the comments you get, for ...
To convert an associative array into a JSON String in PHP, calljson_encode()function and pass the associative array as argument. This function can take other optional parameters also that effect the conversion to JSON String. Syntax The syntax ofjson_decode()function is ...
letthing:Series=tryJSONDecoder().decode(Series.self,from:decoderedJSON) Still have no clue and haven't found an answer how to initialize the Series dictionary correctly... this just throws an erry that JSON decoder wants to decode an array: @...