21%=massingofNaCl100mLoftotalsolution×100% Solving for the mass of solute you find: 21=massingofNaCl This means that there are 21 grams of NaCl in every 100 mL of solution. To find molarity you will need to convert this number of grams into moles by using the molar mass of NaCl: 21...
Use the formulax= (c÷V) × 100 to convert the concentration (c) and volume (V) of the final solution to a percentage. In the example,c= 60 ml andV= 350 ml. Solve the above formula forx, which is the percentage concentration of the final solution. In this case,x= (60 ml ÷ ...
how would I determine the molarity of this solution I have made? I cant thank you guys enough for the help, and tolerance to my chemistry n00bness