cout <<"LCM of "<< num1 <<" and "<< num2 <<" is "<< calculateLCM(num1, num2) << endl; intnum3 =10, num4 =2; cout <<"LCM of "<< num3 <<" and "<< num4 <<" is "<< calculateLCM(num3, num4) << endl; intnum5 =88, num6 =11; cout <<"LCM of "<< num5...
flag,lcm); } int main() { while(cin>>n>>m) { n--; for(int i=0;i<m;i++) { scanf("%d",&a[i]); if(!a[i]) i--,m--; } ans=0; for(int i=0;i<m;i++) dfs(i,1,a[i]); printf("%lld\n",ans); } return 0; } 本文参与 腾讯云自媒体同步曝光计划,分享自作者...
C program to find the roots of a quadratic equation C program to find the GCD (Greatest Common Divisor) of two integers C program to find the LCM (Lowest Common Multiple) of two integers C program to calculate the area of a triangle given three sides C program to calculate ...
Python Program to Find LCM WAP in C++ & Python to find whether a number is a palindrome or not WAP to convert a given number of days into years, weeks and days WAP to calculate the sum of two numbers Python Program to Count the Number of Each Vowel Vinay...
In general, if you have the prime factorization of the number n, then to calculate how many divisors it has, you take all the exponents in the factorization,
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The latter case is the base case of our Java program to find the GCD of two numbers using recursion. You can also calculate the greatest common divisor in Java without using recursion but that would not be as easy as the recursive version, but still a good exercise from the coding intervi...