cout <<"LCM of "<< num1 <<" and "<< num2 <<" is "<< calculateLCM(num1, num2) << endl; intnum3 =10, num4 =2; cout <<"LCM of "<< num3 <<" and "<< num4 <<" is "<< calculateLCM(num3, num4) << endl; intnum5 =88, num6 =11; cout <<"LCM of "<< num5...
C program to calculate HCF of two numbers C program to multiply two numbers using plus operator C program to demonstrate example of global and local scope C program to demonstrate example of floor and ceil functions Write a C program to evaluate the net salary of an employee give...
//C# program to check given numbers are//the pair of amicable numbers or not.usingSystem;classDemo{staticboolIsAmicable(intnumber1,intnumber2){intsum1=0;intsum2=0;intX=0;for(X=1;X<number1;X++){if(number1%X==0){sum1=sum1+X;}}for(X=1;X<number2;X++){if(number2%X==0){sum...
The latter case is the base case of our Java program to find the GCD of two numbers using recursion. You can also calculate the greatest common divisor in Java without using recursion but that would not be as easy as the recursive version, but still a good exercise from the coding intervi...