How many three-digit numbers are there that have the sum of their digits equal to 10? 答案 54.When the hundred digit is 1: 109, 118, 127, ⋯,190, there are 10 numbers;when the hundred digit is 2: 208, 217, 226,⋯,280, there are 9 numbers;when the hundred digit is 3: 307...
所以有8种选择, 一共可以组成9×9×8=648个没有重复数字的三位数.结果一 题目 没有重复数字的三位数有多少个?How many three-digit numbers are there with no repeating digits? 答案 648.相关推荐 1没有重复数字的三位数有多少个?How many three-digit numbers are there with no repeating digits?反馈...
To find how many three-digit numbers can be formed with no repeated digits, we can break the problem down into steps based on the placement of the digits.1. Identify the Structure of a Three-Digit Number: A three-digit numbe
How many 3 digit numbers are there such that the sum of the digits is 17?Writing Simple Equations.Writing simple equations with certain constraints is an easy task to do if we can figure out which digit has which constraints. Certain constraints to keep in mind while solving ...
Answer to: How many three-digit numbers are there with 3 in the unit place? (i) with repetition. (ii) without repetition. By signing up, you'll get...
17.有多少个三位数,其各位数字的乘积是质数 17. How many three-digit numbers are there such that(注:1不是质数)? the product of their digits is a prime number?(A)15 (B)12 (C)17 (Remember 1 is not a prime number.)(D)20 (E)21 (A)15 (B)12 (C)17(D)20 (E)21 答案 17.B相...
How many three-digit numbers are there in which every digit is a multiple of 4?相关知识点: 数与代数 数的认识 整数的认识 万以内数的认识 试题来源: 解析 18. 个位数中是4的倍数的数字有:0,4,8,三位数中,每个数位上的数字是4的倍数的数有:444,888,448,484,844,488,848,884,400,408,480,804...
How many four digit numbers are there in all? View Solution How many 4-digit numbers are there when a digit may be repeated an number of times? View Solution How many six-digit numbers are there in which no digit is repeated, even digits appear at even places, odd digits appear at odd...
To solve the problem of finding how many 4-digit numbers can be formed without repetition of digits, where each number is divisible by 5, we can break it down into two cases based on the last digit.Step 1: Understand the conditions</str
第一位数：9种 (10种中减去0）第二位：10种-1种（第一位里选走的）第三位：9种-1种（10个数选走了2）