Range of the projectile The range of the projectile is the total horizontal distance traveled in the flight time. Then, we can write down the equation as: r=Vt=V2hgr=Vt=Vg2h Again, this formula would be more complicated if the angle weren't set to 0°. If you're curious to see it...
If an object follows the parabolic path under the force of gravity, then the motion of the object is the projectile motion. If the initial velocity of the object is u, g is the acceleration due to gravity, and θ is ...
Calculate the electric field E produced by the sheet of charge using the formula E = \frac{\sigma}{2\epsilon_0}, where \sigma is the surface charge density and \epsilon_0 is the permittivity of free space (approximately 8.85×10^{-12} C^2/N·m^2). ...
To solve the problem of finding the angle at which an object should be projected so that the maximum height reached is equal to the horizontal range, we can follow these steps:1. Understand the Formulas: - The formula for ma
As discussed previously, the horizontal distance traveled in the horizontal jump was calculated as Xlanding=Xt.o.+VXt.o.⋅2⋅VYt.o.g By analyzing the right-hand side of this formula, it can be derived that the second term is maximized when the projection angle is 45 deg. However,...
To solve the problem step by step, we will break down the motion of the stone into its horizontal and vertical components.Step 1: Determine the angle of projection The angle of projection θ is given as: \( \theta = \tan^{-1}\l
To find the magnitude of the centripetal acceleration of the stone while it is in circular motion, we can follow these steps:Step 1: Understand the motion after the string breaks When the string breaks, the stone will move hori
To solve the problem of determining the angle at which a player should throw a ball to achieve maximum distance and maximum height, we can break it down into two parts:Part (i): Maximum Distance1. Understanding P