The graph shows the height of a ball thrown into the air, where time, t, is in seconds and height, h(t), is in metres. Using the graph shown below, what is the algebraic model? ( ) A. h(t)=-5(t+1.4)^2+18 B. h(t)=-5(t-18)^2+1.4 C. h(t)=5(t-1.4)^2+1...
A ball is thrown in the air. Its height, h (in meters), is given by h = −4.9t= + 20t + 2 where t is the time (in seconds). What is the height of the ball after 4 seconds? A: 17.1 mB: 4.9 mC: 3.6 mD: 20 m 相关知识点: 试题来源: 解析 CNone 反馈 收藏 ...
When the ball is thrown upward, it is constantly accelerating in the direction of the gravitational force. When the ball reaches its maximum height,...Become a member and unlock all Study Answers Start today. Try it now Create an account Ask a quest...
Answer to: If a ball is thrown into the air with a velocity of 42 ft/s, its height (in feet) after t seconds is given by y = 42t - 16t^2. Find...
英语翻译If a ball is thrown in the air with a velocity 48 ft/s,its height in feet t seconds later is given by y = 48t − 16t2.(a) Find the average velocity for the time period beginning when t = 2 and lasting 0.5 second.
A ball is thrown in the air. Its height, h (in yards), is given by h = −4.9t + 20t + 2 where t is the time (in seconds). What is the height of the ball at the instant it is thrown? A: 0 yd B: 4.9 yd C: 2 yd...
1. A ball is thrown into the air from an initial height of 10 feet. Its height above the ground, in feet, t seconds after it is thrown is given by the function h(t) = -16t +27t + 10. How long will it take (in seconds) for the ball to hit the ground after it is thrown?
Quadratic Functions Word Problem数学,函数,方程A ball is thrown up into the air. Its height h, in metres, after t seconds is h= -4.9t^2 +38t+1.75. For what length of time is the ball above 50m?希望解答.希望写出过程.谢谢.
Answer to: If a ball is thrown into the air with a velocity of 35 ft/s, its height after t seconds is given y = 35t - 16t^2 . Find the velocity...
<p>To find the work done on the ball by air resistance, we can use the work-energy theorem, which states that the total work done on an object is equal to the change in its kinetic energy. </p><p>Let's break down the solution step by step:</p><p><strong>