这个类是为了创建一个TCP或者说是本地一个服务器。 net.Server是EventEmitter,所以它拥有下面一些event. Event: 'close' 当服务器关闭的时候会emit。注意:要所有链接都断掉!!! Event: 'connection' <net.Socket>这个一个连接对象 当客服端与服务器形成一个新的连接的时候,就会emit.回调函数里的参数就是net.Socke...
给.NET框架下的高级语言定义的一套CIL的定义、规则或标准,这套规则规定了语言可以做什么,不可以做什么以及具有哪些特性。任何满足了CTS规则的语言就是面向.NET框架的语言,C#、VB.NET就是微软自己开发的符合CTS规则的.NET高级开发语言。值得注意的是,.NET下的C++是微软推出的符合CTS标准的语言,由于CTS规则不支持多继...
hdu1045 Fire Net(dfs) 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1045 题目大意: * //这题意思是给出一张图,图中'X'表示wall,'.'表示空地,可以放置blockhouse //同一条直线上只能有一个blockhouse,除非有wall隔开,问在给出的图中 //最多能放置多少个blockh......
CSF-net: Cross-Modal Spatiotemporal Fusion Network for Pulmonary Nodule Malignancy Predicting Proposed method This code is a pytorch implementation of our paper "CSF-net: Cross-Modal Spatiotemporal Fusion Network for Pulmonary Nodule Malignancy Predicting". It consists of three components: (a) spatial...
二分图匹配在HDU 1045 Fire Net中的应用有哪些? 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1045 题意是有个n*n地图,地图中有空地'.'和墙'X',然后我们要在空地上安置大炮,为了防止大炮打大炮,一行和一列上只能有一台大炮,问最多能放多少大炮。 比较好想的思路就是爆搜,我们用dfs去一个一...
hdu 1045 Fire Net 1.类似八皇后问题,但同行同列若有墙则可再放置,回溯+dfs 2.二分匹配问题,X部和Y部满足条件的交叉点即为所求 ... HDU 1045 Fire Net 题目传送门:https://vjudge.net/problem/HDU-1045 题意:在一个n*n(n<=4)的区域内建造炮塔,炮塔与炮塔不能在同一行和同一列除非中间有城墙...
HDU-1045,Fire Net(经典DFS) Problem Description: Suppose that we have a square city with straight streets. A map of a city is a square board with n rows and n columns, each representing a street or a piece of wall. A blockhouse is a small castle that has four openings through which ...
【HDU - 1045】Fire Net (dfs 或二分图) 题干: Suppose that we have a square city with straight streets. A map of a city is a square board with n rows and n columns, each representing a street or a piece of wall. A blockhouse is a small castle that has four openings through which...
char map[5][5]; int n,ans; bool leagal(int x,int y) { bool have; have = false; map[x][y] = 'B'; for(int i=0;i<n;i++) { if(map[x][i] == 'B') if(have) return false; else have = true; if(map[x][i] == 'X') ...
二分图代码: #include <cstdio>#include<iostream>#include<algorithm>#include<cstring>usingnamespacestd;charG[5][5];intmap[20][20],col[5][5],row[5][5];intmatch[20],vis[20];intcntx ,cnty,n;boolFind(intu){for(inti=0; i<cnty; i++){intx =i;if(!vis[x] &&map[u][x]){ ...