In order to find the HCF of three numbers, we use the following procedure. Let us understand this using the steps and the example given below.Step 1: First, find the HCF of the largest and the smallest of the given numbers. Step 2: Then, find the HCF of the third number and the ...
the divisor of the last step is the hcf. how to find the hcf of three numbers find the steps to calculate the hcf of the 3 numbers given to us. 1) calculate the hcf of 2 numbers. 2) then find the hcf of the 3rd number and the hcf found in step 1. 3) the hcf you got in...
The LCM and HCF calculator (also called the LCD and GCD finder) will determine the least common multiple and greatest common factor of a set of two to n numbers. You can also compute the LCM and HCF by hand or use the LCM calculator or the HCF calculator
The Highest Common Factor or HCF (also known as theGreatest Common FactororGCF) is the highest factor that two or more numbers share or have in common. It has a notation ofHCF (a,b) =n, whereaandbare the numbers that have HCF andnas their HCF. There are different methods to obtain ...
In this article, we will find HCF of two numbers using factorisation and division method, with the help of solved examples. Also, find the HCF of three numbers, here at BYJU’S.
(3)The LCM of three numbers is 120. By using the method of solving, determine which of the following numbers can not be it's LCM. 12 24 8 35 Answer) d) 35 3. Answer the following questions: a)Is it possible that the HCF of two numbers is 16 and LCM as 380. Give reason to ...
HCF of 12, 24 and 36 is the largest possible number which divides 12, 24 and 36 without leaving any remainder. The methods to compute the HCF of 12, 24, 36 are explained here.
There are three numbers a,b, c such that HCF (a, b) = l, HCF (b, c) = m and HCF (c, a) = n. HCF (l, m) = HCF (l, n) = HCF (n, m) = 1. Find LCM of a, b, c. (The answer can be "This cannot be determined"). ...
// Java program to calculate the // HCF of two numbers import java.util.Scanner; public class Main { static int CalHcf(int num1, int num2) { int temp = 0; if (num1 == 0 || num2 == 0) return 0; while (num2 != 0) { temp = num1 % num2; num1 = num2; num2 = ...
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