百度试题 结果1 题目(vi)27 and 63Prime factors of 27 = 1Prime factors of 63 = 3HCF of 27 and 63 =2 相关知识点: 试题来源: 解析 133 反馈 收藏
HCF of 27 and 63 is the largest possible number which divides 27 and 63 without leaving any remainder. The methods to compute the HCF of 27, 63 are explained here.
(4)27, 633-|||-27-|||-3-|||-9-|||-3-|||-3-|||-1-|||-3-|||-63-|||-3-|||-21-|||-7-|||-7-|||-127 = 3 × 3 × 363 = 3 × 3 × 7HCF = 3 × 3 = 9Therefore the HCF of 27, 63 is 9 (5)36, 842-|||-36-|||-2-|||-18-|||-3-|||-9-...
: (i) cell cycle progression via modulation of the activities of the E2F family [20,21,22]; (ii) embryonic stem cell pluripotency and metabolism via E2F and THAP proteins [23,24,25]; (iii) metabolism and nuclear respiratory control via GABP and the coactivators PGC and PRC [26,27]. ...
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病例64:侯某某,女,57岁,确诊病例63号方某某表嫂。现住岳阳楼区八一招待所附近军分区干休所,1月27日收治于市一人民医院,2月2日确诊。 病例67:叶某某,女,59岁,现住在岳阳楼区炮台山家属楼。与丈夫易某(疑似病例)、儿子易某(疑似病例)、小叔子易某某(确诊病例47)有密切接触。1月31日收治于岳阳市第一人民医院...