HCF of 40, 42 and 45 is the largest possible number that divides 40, 42 and 45 exactly without any remainder. The factors of 40, 42 and 45 are (1, 2, 4, 5, 8, 10, 20, 40), (1, 2, 3, 6, 7, 14, 21, 42) and (1, 3,
HCF of 18 and 45 is the largest possible number which divides 18 and 45 without leaving any remainder. The methods to compute the HCF of 18, 45 are explained here.
Lcf- and lcf/hcf-behaviour of the superalloy mar-m247lcGelmedin, DomninLang, Karlheinz
To find the square of the HCF (Highest Common Factor) of the numbers 36, 40, and 48, we will follow these steps:Step 1: Find the prime factorization of each number. - For 36: - 36 can be factored as \( 2 \ti
Given that a+b=216, the HCF of a and b is 18. If a. 相关知识点: 试题来源: 解析 18,198 or 90,126.. 本题过程如下: ①d=18; ②设a=18x,b=18y,则x、y互质,即(x,y)=1; ③题目条件变为18x+18y=216,即x+y=12; ④和为12,还互质的两数,只能是1、11或5、7; ⑤对应本题...
VOL ≤ 0.4V, and IOL ≥ 3.2mA). June 1989 1/12 HCC/HCF4049UB/4050B SCHEMATIC DIAGRAMS (1 of 6 identical units) 4049UB 4050B ABSOLUTE MAXIMUM RATINGS Symbol Parameter Supply Voltage : HCC Types HCF Types Value Unit VDD * –0.5 to + 20 –0.5 to + 18 V ...
The HCF and LCM of two numbers is 9 and 459 respectively. If one of the number is 27, then the other number is( )?A. 153B. 150C. 459D. 135 相关知识点: 试题来源: 解析 A. 153 设另一个数为x。根据公式:两数乘积 = HCF × LCM,可得:27 × x = 9 × 459 解得:x = (9 × ...
To find the difference between the HCF (Highest Common Factor) and LCM (Lowest Common Multiple) of the numbers 184 and 345, we will follow these steps:Step 1: Find the Prime Factorization of Each Number - For 184</stron
HCF of 40, 60 and 75 is the largest possible number which divides 40, 60 and 75 without leaving any remainder. The methods to compute the HCF of 40, 60, 75 are explained here.
1,2,4,5,8,10,20,40 and 1,2,4,8,16,32,64or 2×2×2×5 and 2×2×2×2×2×2M1 for start to list factors - must be at least 4 for each of 40 and 64 or prime factorisation of both numbers with at least 2 stages correct eg 40=2×20=2×4×5 could benumbers on tree...