HCF of 40, 42 and 45 is the largest possible number which divides 40, 42 and 45 without leaving any remainder. The methods to compute the HCF of 40, 42, 45 are explained here.
HCF of 32 and 40 is the largest possible number which divides 32 and 40 without leaving any remainder. The methods to compute the HCF of 32, 40 are explained here.
The HCF of44x5y4,88x6y5, and66x7y6___. View Solution The HCF of4y4x−9y2x3and4y2x2+6yx3is View Solution Doubtnut is No.1 Study App and Learning App with Instant Video Solutions for NCERT Class 6, Class 7, Class 8, Class 9, Class 10, Class 11 and Class 12, IIT JEE prep...
The slope of common tangents to x^(2)+4y^(2)=4 and x^(2)+y^(2)=3 is m ... 02:33 সরল করো(x+y)^(4)-4y(x+y)^(3)+6y^(2)(x+y)^(2)-4y^(3)(x+y)+y^(4) 03:02 সরল করো(x+y)^(4)-4y(x+y)^(3)+6y^(2)(x+y)^(2)-4y...
HCF of co-prime numbers 4 and 15 was found as follows by factorisation:4 = 2 × 2 and 15 =3 × 5 since there is no common prime factor, so HCF of 4 and 15 is 0.Is the answer correct? If not, what is the correct HCF?
HCF and LCM definitions, formulas and examples are provided here. Visit BYJU’S to learn the full form of LCM in Maths and the full form of HCF in Maths and their methods.
根据题目中给出的信息，2是4和x的最大公约数（HCF）。我们可以利用这个信息来解出x的值。我们知道4和x的最大公约数是2。这意味着x一定是2的倍数。所以，我们可以表示x为2乘以一个未知整数k：x = 2k其中k是任意整数。x可以是任意一个2的倍数。具体的数值取决于k的值。因此，无法确定x的具体...
(4)27, 633-|||-27-|||-3-|||-9-|||-3-|||-3-|||-1-|||-3-|||-63-|||-3-|||-21-|||-7-|||-7-|||-127 = 3 × 3 × 363 = 3 × 3 × 7HCF = 3 × 3 = 9Therefore the HCF of 27, 63 is 9 (5)36, 842-|||-36-|||-2-|||-18-|||-3-|||-9-...
Common multiples are: 20, 40, 60, 80, …. We can see than 20 is the Least common multiples. That is the LCM Method to find LCM Let’s take an example: Find LCF of 24, 36 and 50. Step 1: Write them in Prime form 24 = 23 x 3 ...
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