Example: Find the HCF of 30 and 42.Solution: We will list the factors of 30 and 42. The factors of 30 are 1, 2, 3, 5, 6, 10, 15, and 30 and the factors of 42 are 1, 2, 3, 6, 7, 14, 21, and 42. Clearly, 1, 2, 3, and 6 are the common factors of 30 and 42...
HCF of 40, 42 and 45 is the largest possible number which divides 40, 42 and 45 without leaving any remainder. The methods to compute the HCF of 40, 42, 45 are explained here.
Class 14 MATHS Find the HCF of: ... Find the HCF of: (a) 42, 63 and 140 (b) 108, 288 and 360 Video Solution| ShareSave Answer Step by step video & image solution for Find the HCF of: (a) 42, 63 and 140 (b) 108, 288 and 360 by Maths experts to help you in doubts &...
Fatigue life variability of a newly developed third-generation Ni-based single crystal superalloy resulting from different solution heat treatment procedures has been investigated in low cycle fatigue (T = 650 degrees C/R-sigma = 0.05/f = 0.5 Hz), high cycle fatigue (T = 950 degrees C/R-...
(v) 32, 56 and 46 Solution: Question 4. Use a method of your own choice to find the H.C.F. of : (i) 45, 75 and 135 (ii) 48, 36 and 96 (iii) 66, 33 and 132 (iv) 24, 36, 60 and 132 (v) 30, 60, 90 and 105 ...
Due to limited solid solubility of Si in Al as temperature drops (1.65 wt.% at 850 K, 0.06 wt.% at 300 °C), Si particles are rejected to the boundaries of the solid solution. However, this limited solid solubility is extended in high cooling rates, giving way to a decreased solute ...
Due to limited solid solubility of Si in Al as temperature drops (1.65 wt.% at 850 K, 0.06 wt.% at 300 °C), Si particles are rejected to the boundaries of the solid solution. However, this limited solid solubility is extended in high cooling rates, giving way to a decreased solute ...
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HCF of 84 and 120 is the largest possible number which divides 84 and 120 without leaving any remainder. The methods to compute the HCF of 84, 120 are explained here.