HCF of 404 and 96 is the largest possible number that divides 404 and 96 exactly without any remainder. The factors of 404 and 96 are 1, 2, 4, 101, 202, 404 and 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96 respectively. There are 3 commonly used methods to find the HCF ...
HCF of 90 and 105 is the largest possible number which divides 90 and 105 without leaving any remainder. The methods to compute the HCF of 90, 105 are explained here.
百度试题 结果1 题目Find the LCM and HCF of 234 and 135.相关知识点: 试题来源: 解析 HCF is 9, LCM is 3510 反馈 收藏
解析 HCF is 9, LCM is 3510 234=2×32×13 135=33×5 HCF is 32=9 LCM is 2×33×5×13=3510结果一 题目 Find the LCM and HCF of 234 and 135. 答案 HCF is 9, LCM is 3510相关推荐 1Find the LCM and HCF of 234 and 135.反馈 收藏 ...
18 has two prime factors: 21 and 32 (since 18 = 2 * 3 * 3).28 have two prime factors: 22 and 71 (since 28 = 2 * 2 * 7). Now, from both numbers, take the least power of each prime factor.The smallest power of 2 is 21.The smallest power of 3 is 31.There is no ...
百度试题 结果1 题目13 Find the highest common factor (HCF) of 12 and 30.6[] 相关知识点: 试题来源: 解析 6 反馈 收藏
To find the Highest Common Factor (HCF) of 16 and 32, we can follow these steps:Step 1: Factor the numbers First, we need to factor both numbers into their prime factors.- For 16: - 16 can be divided
百度试题 结果1 题目Find the HCF and LCM of 42 and 63.HCF: LCM: 相关知识点: 试题来源: 解析 21;126 42=2×3×763=3×3×7Therefore, HCF=3×7=21 and LCM=2×3×3×7=126反馈 收藏
(b) Find the HCF of 48x2(x+3)2(2x−1)3(x+1) and 60x3(x+3)(2x−1)2(x+2). Video Solution Text SolutionVerified by Experts (a) Find f(x) = 28x4 and g(x) = 70x6. Writing f(x) and g(x) as a product of powers of irreducible factors , we have f(x) = 22...
The HCF of 56 and 57 is 1. Learn to calculate the Highest Common Factor of 56 and 57 using prime factorisation, long division method and listing common factors with simple steps, at BYJU’S.