Example: Find the HCF of 30 and 42.Solution: We will list the factors of 30 and 42. The factors of 30 are 1, 2, 3, 5, 6, 10, 15, and 30 and the factors of 42 are 1, 2, 3, 6, 7, 14, 21, and 42. Clearly, 1, 2, 3, and 6 are the common factors of 30 and 42...
HCF of 18 and 20 is the largest possible number which divides 18 and 20 without leaving any remainder. The methods to compute the HCF of 18, 20 are explained here.
18 has two prime factors: 21 and 32 (since 18 = 2 * 3 * 3).28 have two prime factors: 22 and 71 (since 28 = 2 * 2 * 7). Now, from both numbers, take the least power of each prime factor.The smallest power of 2 is 21.The smallest power of 3 is 31.There is no ...
解析 HCF is 9, LCM is 3510 234=2×32×13 135=33×5 HCF is 32=9 LCM is 2×33×5×13=3510结果一 题目 Find the LCM and HCF of 234 and 135. 答案 HCF is 9, LCM is 3510相关推荐 1Find the LCM and HCF of 234 and 135.反馈 收藏 ...
7 57 = 3 × 19 there is no common prime factor between 56 and 57. therefore, hcf (56, 57) = 1 hcf of 56 and 57 by long division method in this method, to find the hcf of 56 and 57, we use the steps mentioned below: step 1: divide the largest number by the smallest number...
结果1 题目 Bookwork code: L64X Work out the highest common factor (HCF) of 8 and 10.(Hint: first write out all of the factors of 8 and all of the factors of 10)Answer OM四 .1834ENG/2021 相关知识点: 试题来源: 解析 Hence answe s?Civen= and 10 反馈 收藏 ...
解析 HCF is 9, LCM is 3510 结果一 题目 Find the LCM and HCF of 234 and 135. 答案 HCF is 9, LCM is 3510234=2×32×13135=33×5HCF is 32=9LCM is 2×33×5×13=3510相关推荐 1Find the LCM and HCF of 234 and 135.反馈 收藏 ...
百度试题 结果1 题目Find the LCM and HCF of 234 and 135.相关知识点: 试题来源: 解析 HCF is 9, LCM is 3510 反馈 收藏
,Prime Factorizationis a method of getting the factors of a number that areprime numbers. Whether we are using Factor Tree or Tabular Division, our goal is to end up with prime factors, multiply them and declare it as the HCF. The first five prime numbers are 2, 3, 5, 7, and 11....
⇒ HCF = 2×7×x4=14x4 (b) Let f(x) = 48x2(x+3)2(2x−1)3(x+1) and g(x) = 60x3(x+3)(2x−1)2(x+2). Writing f(x) and g(x) as the product of the powers of irreducible factors , we have f(x) = 24×3×x2(x+3)2(2x−1)3(x+1) g (x) ...