HCF of 15 and 20 is the largest possible number which divides 15 and 20 without leaving any remainder. The methods to compute the HCF of 15, 20 are explained here.
HCF of co-prime numbers 4 and 15 was found as follows by factorisation:4 = 2 × 2 and 15 =3 × 5 since there is no common prime factor, so HCF of 4 and 15 is 0.Is the answer correct? If not, what is the correct HCF?
HCF of 255 and 867 is the largest possible number which divides 255 and 867 without leaving any remainder. The methods to compute the HCF of 255, 867 are explained here.
Definition of LCM and HCF Lowest Common Multiple (LCM):The least or smallest common multiple of any two or more given natural numbers are termed asLCM. For example, LCM of 10, 15, and 20 is 60. Highest Common Factor (HCF):The largest or greatest factor common to any two or more give...
The formula to compute the Least Common Multiple of Fractions is given below i.e. LCM of Fractions = LCM of Numerators/HCF of Denominators. For Example LCM of Fractions 5/4 and 3/8 can be written as LCM(5/4, 3/8) = LCM(5, 3)/HCF(4, 8) = 15/4 ...
15 =3× 5 18 = 233 This means that3is the Highest Common Factor of 15 and 18 orHCF (15, 18) = 3. Example 2: Using a Table Let us use 15 and 18 again to see the difference of this method from theFactor Tree method. For the Table Method, we need to make a table with two...
Find the HCF of the polynomial30(x2−3x+2)and50(x2−2x+1) View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium NCERT Solutions for Class 10 English Medium ...
Find the HCF of12,34and45 View Solution IfP=23.310.5,Q=25.3.7, then find the HCF of P and Q. View Solution Doubtnut is No.1 Study App and Learning App with Instant Video Solutions for NCERT Class 6, Class 7, Class 8, Class 9, Class 10, Class 11 and Class 12, IIT JEE prep,...
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So Finally the HCF of the numbers 150, 210 & 375 is 15. Example : 2 Find the greatest number that will divided 640, 710 and 1526 so as to leave 11,7 &9 as a remainders respectively. Step 1: Subtract all numbers with there respective remainders i.e 640-11=629, 710-7=703 and ...