HCF of 18 and 45 is the largest possible number which divides 18 and 45 without leaving any remainder. The methods to compute the HCF of 18, 45 are explained here.
HCF of 1260 and 7344 is the largest possible number that divides 1260 and 7344 exactly without any remainder. The factors of 1260 and 7344 are 1, 2, 3, 4, 5, 6, 7, 9, 10, 12, 14, 15, 18, 20, 21, 28, 30, 35, 36, 42, 45, 60, 63, 70, 84, 90, 105, 126, 140, 1...
百度试题 结果1 题目1. (a) Find the HCF of 42, 66 and 78.(b)Find the LCM of 9, 16 and 18. 相关知识点: 试题来源: 解析 1. (a) 6(b) 144 反馈 收藏
18 has two prime factors: 21 and 32 (since 18 = 2 * 3 * 3).28 have two prime factors: 22 and 71 (since 28 = 2 * 2 * 7). Now, from both numbers, take the least power of each prime factor.The smallest power of 2 is 21.The smallest power of 3 is 31.There is no ...
Video Solution free crash course Study and Revise for your exams Unlock now | ShareSave Answer Step by step video & image solution for Find the HCF of: (a) 42, 63 and 140 (b) 108, 288 and 360 by Maths experts to help you in doubts & scoring excellent marks in Class 14 exams.Updat...
View Solution Find the HCF of 6 and 12. View Solution Find the HCF:105,154 View Solution Find the HCF:57,75,102 View Solution NAND LAL PUBLICATION-PLAYING WITH NUMBERS -EXERCISE 3.6 Find the HCF of 18, 48 01:51 Find the HCF of 30,42 01:38 Find the HCF of 18,60 01:41 Find th...
LCM of 8 and 9 = 2³ × 3² = 8 × 9 = 72 HCF of 8 and 9 = 1 Product of 8 and 9 = 8 × 9 = 72 Hence, LCM of co-prime numbers = Product of the numbers. Therefore, verified. Example 3: Find the HCF of 12/25, 9/10, 18/35, 21/40. ...
12 (a) Find the Highest Common Factor (HCF) of 30 and 42(b) Find the Lowest Common Mutiple (LCM) of 30 and 45 相关知识点: 试题来源: 解析 (a) 30=2×3×542=2×3×7HCF=2×3=6(b) 30,60,90,...45,90,135,...90 反馈 收藏 ...
The HCF of 56 and 57 is 1. Learn to calculate the Highest Common Factor of 56 and 57 using prime factorisation, long division method and listing common factors with simple steps, at BYJU’S.
HCF of co-prime numbers 4 and 15 was found as follows by factorisation:4 = 2 × 2 and 15 =3 × 5 since there is no common prime factor, so HCF of 4 and 15 is 0.Is the answer correct? If not, what is the correct HCF?