If one of the numbers is 640, find the other number. 相关知识点: 试题来源: 解析 144 题目中给出了两个数的HCF为16、LCM为5760,已知其中一个数为640,要求另一个数。根据数学关系式“两数之积=HCF×LCM”,将已知数值代入得640×另一数=16×5760。计算得另一数=(16×5760)/640=92160/640=144。验证...
HCF of 16 and 27 is the largest possible number which divides 16 and 27 without leaving any remainder. The methods to compute the HCF of 16, 27 are explained here.
1,2,4,5,8,10,20,40 and 1,2,4,8,16,32,64or 2×2×2×5 and 2×2×2×2×2×2M1 for start to list factors - must be at least 4 for each of 40 and 64 or prime factorisation of both numbers with at least 2 stages correct eg 40=2×20=2×4×5 could benumbers on tree...
HCF of 64 and 72 is the largest possible number which divides 64 and 72 without leaving any remainder. The methods to compute the HCF of 64, 72 are explained here.
To find the Highest Common Factor (HCF) of 16 and 32, we can follow these steps:Step 1: Factor the numbers First, we need to factor both numbers into their prime factors.- For 16: - 16 can be divided
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Given that a+b=216, the HCF of a and b is 18. If a. 相关知识点: 试题来源: 解析 18,198 or 90,126.. 本题过程如下: ①d=18; ②设a=18x,b=18y,则x、y互质,即(x,y)=1; ③题目条件变为18x+18y=216,即x+y=12; ④和为12,还互质的两数,只能是1、11或5、7; ⑤对应本题...
The HCF and LCM of two numbers is 9 and 459 respectively. If one of the number is 27, then the other number is( )?A. 153B. 150C. 459D. 135 相关知识点: 试题来源: 解析 A. 153 设另一个数为x。根据公式:两数乘积 = HCF × LCM,可得:27 × x = 9 × 459 解得:x = (9 × ...
The accumulation of irreversible plastic deformation in the ferrite grains and the strength of microstructural barriers in the vicinity of the plastically deformed grains are mainly determining the total fatigue life. In order to assess quantitatively the contribution of irreversible plastic deformation a ...
HCF of 40, 60 and 75 is the largest possible number which divides 40, 60 and 75 without leaving any remainder. The methods to compute the HCF of 40, 60, 75 are explained here.