HCF of 12 and 16 is the largest possible number which divides 12 and 16 without leaving any remainder. The methods to compute the HCF of 12, 16 are explained here.
HCF of 1872 and 1320 is the largest possible number which divides 1872 and 1320 without leaving any remainder. The methods to compute the HCF of 1872, 1320 are explained here.
Learn Properties of HCF and LCM and the relation between LCM and HCF of natural numbers with examples. Formula to find HCF and LCM of fractions at BYJU'S.
Lowest Common Multiple (LCM):The smallest number (other than zero) that is the common multiple of any two or more given natural numbers are termed as LCM. For example, LCM of 6, 8, and 12 is 24. Highest Common Factor (HCF):The greatest factor which is common to any two or more gi...
Since 16 and 48 are both multiples of 16, we are going to use 16 as the first divisor. Then write the quotients below their respective dividends. We can notice here that we are already left with numbers that cannot be divided by the same number. This means that we can now stop the ...
Since 16 and 48 are both multiples of 16, we are going to use 16 as the first divisor. Then write the quotients below their respective dividends. We can notice here that we are already left with numbers that cannot be divided by the same number. This means that we can now stop the ...
HCF and LCM definitions, formulas and examples are provided here. Visit BYJU’S to learn the full form of LCM in Maths and the full form of HCF in Maths and their methods.
52. What is the HCF of 18 and 28? Answer The correct answer is:D) 6 Explanation The explanation is: 18 has two prime factors: 21and 32(since 18 = 2 * 3 * 3). 28 have two prime factors: 22and 71(since 28 = 2 * 2 * 7). ...
23) Find the LCM of 9 and 12.24) Find the HCF of 16 and 28.25) Write the product in the boxes.10*20=▱ 相关知识点: 试题来源: 解析 2CMof9.121HH83(19*121)/(3.4) 40(x_2=2024(16)/4x_2.7 ∴2cm=3*3*4 ∴HCF=14 =√(3-6) ...
根据题目中给出的信息,2是4和x的最大公约数(HCF)。我们可以利用这个信息来解出x的值。我们知道4和x的最大公约数是2。这意味着x一定是2的倍数。所以,我们可以表示x为2乘以一个未知整数k:x = 2k其中k是任意整数。x可以是任意一个2的倍数。具体的数值取决于k的值。因此,无法确定x的具体...