Solution: First, we will find the HCF of the two numbers 126 and 180. The HCF of 126 and 180 = 18. Then, we will find the HCF of the third number, which is 162, and the HCF of the two numbers obtained in the previous step, that is, 18. This will give the final HCF of ...
Example: Find the HCF of 126, 162 and 180. Solution: By prime factorisation, we can write the given numbers as; 126 = 2x3x3x7 162 = 2x3x3x3x3 180 = 2x2x3x3x5 Taking out the common factors of 126, 162 an d180, we get: ...
HCF of 405 and 2520 is the largest possible number which divides 405 and 2520 without leaving any remainder. The methods to compute the HCF of 405, 2520 are explained here.
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