HCF of 12 and 30 is the largest possible number which divides 12 and 30 without leaving any remainder. The methods to compute the HCF of 12, 30 are explained here.
252 = 22× 32× 7 288 = 25× 32 The HCF of these three numbers will be the product of the smallest power of each common prime factor of the three numbers. Thus, HCF of 168, 252, and 288 = 22× 3 = 12 Example 3a: What is the HCF of 2 and 3? Solution: In order to find...
结果1 题目 Bookwork code: L64X Work out the highest common factor (HCF) of 8 and 10.(Hint: first write out all of the factors of 8 and all of the factors of 10)Answer OM四 .1834ENG/2021 相关知识点: 试题来源: 解析 Hence answe s?Civen= and 10 反馈 收藏 ...
HCF and LCM definitions, formulas and examples are provided here. Visit BYJU’S to learn the full form of LCM in Maths and the full form of HCF in Maths and their methods.
解析 HCF is 9, LCM is 3510 234=2×32×13 135=33×5 HCF is 32=9 LCM is 2×33×5×13=3510结果一 题目 Find the LCM and HCF of 234 and 135. 答案 HCF is 9, LCM is 3510相关推荐 1Find the LCM and HCF of 234 and 135.反馈 收藏 ...
HCF of 12x^(2)yz and 16xyz^(2) is 4xyz. 02:00 sqrt((x^(2))/(y^(2)z^(6))) = xy^(-1) z^(-3) 01:40 (a^(2) - 1) + (a - 1) = (a - 1)(a + 2) 01:16 If a + b = 6 and a^(2) - b^(2) = 24 , then a - b = 4. 01:16 The constant term ...
HCF of co-prime numbers 4 and 15 was found as follows by factorisation:4 = 2 × 2 and 15 =3 × 5 since there is no common prime factor, so HCF of 4 and 15 is 0.Is the answer correct? If not, what is the correct HCF?
百度试题 结果1 题目Find the LCM and HCF of 234 and 135.相关知识点: 试题来源: 解析 HCF is 9, LCM is 3510 反馈 收藏
7 57 = 3 × 19 there is no common prime factor between 56 and 57. therefore, hcf (56, 57) = 1 hcf of 56 and 57 by long division method in this method, to find the hcf of 56 and 57, we use the steps mentioned below: step 1: divide the largest number by the smallest number...
52. What is the HCF of 18 and 28? Answer The correct answer is:D) 6 Explanation The explanation is: 18 has two prime factors: 21and 32(since 18 = 2 * 3 * 3). 28 have two prime factors: 22and 71(since 28 = 2 * 2 * 7). ...