HCF of 12 and 36 is the largest possible number which divides 12 and 36 without leaving any remainder. The methods to compute the HCF of 12, 36 are explained here.
HCF of 18 and 24 is the largest possible number which divides 18 and 24 without leaving any remainder. The methods to compute the HCF of 18, 24 are explained here.
The LCM and HCF calculator (also called the LCD and GCD finder) will determine the least common multiple and greatest common factor of a set of two to n numbers. You can also compute the LCM and HCF by hand or use the LCM calculator or the HCF calculator
Learn Properties of HCF and LCM and the relation between LCM and HCF of natural numbers with examples. Formula to find HCF and LCM of fractions at BYJU'S.
HCF and LCM definitions, formulas and examples are provided here. Visit BYJU’S to learn the full form of LCM in Maths and the full form of HCF in Maths and their methods.
Solved Examples on LCM and HCF 1. Find the HCF of the following numbers: 36 48 60 Solution: 36 = 2 x 2 x 3 x 3 48 = 2 x 2 x 2 x 2 x 3 60 = 2 x 2 x 3 x 5 HCF(36, 48, 60)= 2 x 2 x 3 = 12 Therefore HCF of 36, 48, 60 is 12 ...
highest common factor HCF In a set ofnumbers,the highest number which will divide everymember of the set without leaving a remainder.Forexample,12 is the highest common factor of 36,48 andhighest common factor(HCF) In a set of numbers,the highest number which will divide every member of ...
52. What is the HCF of 18 and 28? Answer The correct answer is:D) 6 Explanation The explanation is: 18 has two prime factors: 21and 32(since 18 = 2 * 3 * 3). 28 have two prime factors: 22and 71(since 28 = 2 * 2 * 7). ...
highest common factor HCF In a set ofnumbers,the highest number which will divide everymember of the set without leaving a remainder.Forexample,12 is the highest common factor of 36,48 andhighest common factor(HCF) In a set of numbers,the highest number which will divide every member of th...
根据题目中给出的信息,2是4和x的最大公约数(HCF)。我们可以利用这个信息来解出x的值。我们知道4和x的最大公约数是2。这意味着x一定是2的倍数。所以,我们可以表示x为2乘以一个未知整数k:x = 2k其中k是任意整数。x可以是任意一个2的倍数。具体的数值取决于k的值。因此,无法确定x的具体...