HCF of 12 and 20 is the largest possible number which divides 12 and 20 without leaving any remainder. The methods to compute the HCF of 12, 20 are explained here.
Find the LCM and HCF of 6 and 20 by the prime factorisation method. View Solution Find the LCM and HCF of 6 and 20 by the prime factorisation method. View Solution Exams IIT JEE NEET UP Board Bihar Board CBSE Free Textbook Solutions ...
Factors of 120: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120 Clearly, 6 is the only common factor of 6, 72, and 120. Hence, the HCF of 6, 72, and 120 is 6. Example 2: Find the Highest Common Factor of 168, 252, and 288 by the prime factorizatio...
To find the Highest Common Factor (HCF) of 16 and 32, we can follow these steps:Step 1: Factor the numbers First, we need to factor both numbers into their prime factors.- For 16: - 16 can be divided
Factoring Calculator determines the factors and factor pairs of given numbers in seconds. All you have to do is enter the number in the input to obtain its factors and factor pairs. For Example: 60 Factors are 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60 ...
10 =5x 2 Which of the following is/are the multiple(s) of 10? 5 10 15 20 Answer: 10 and 20; Remember, multiples are products, not factors. Furthermore, multiples of a number should start from itself, so any number that is lower from it is not considered as its multiple. ...
To get the LCM, you need to use the maximum number of prime factors between the two or more given numbers. Example: Find the LCM of \(8\) and \(20\) .First, you need to write the prime factors of each of the given numbers.So, \(8=2 \times 2 \times 2\)\(20=2 \times 2...
If take numbers n1, n2, n3, n4, n5 and x is the common divisible number for all these numbers Than multiples of the number ” x ” are n1, n2, n3, n4 & n5 For example 10,15,20,25,30,35,40 …….. aremultiples of 5
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HCF and LCM Exercise 8C – Selina Concise Mathematics Class 6 ICSE SolutionsQuestion 1. Using the common multiple method, find the L.C.M. of the following : (i) 8, 12 and 24 (ii) 10, 15 and 20 (iii) 3, 6, 9 and 12 Solution:...