To find the HCF of 4 and 9, we will find the prime factorization of the given numbers, i.e. 4 = 2 × 2; 9 = 3 × 3. ⇒ There is no common prime factor for 4 and 9. Hence, HCF (4, 9) = 1. ☛ What is a Prime Number? What is the Relation Between LCM and HCF of...
The common multiples for 4 and 6 are 12,24,36,48…and so on. The least common multiple in that lot would be 12. Let us now try to find out the LCM of 24 and 15. LCM of 24 and 15 = 2 × 2 × 2 × 3 × 5 = 120 ...
4. What is the Fullform of HCF? HCF stands for Highest Common Factor. 5. What is the HCF of 24 and 36? HCF of 24 and 36 is 12. 6. What is the difference between HCF and LCM? LCM of two or more numbers is the smallest number among the common multiples of given numbers whereas...
根据题目中给出的信息，2是4和x的最大公约数（HCF）。我们可以利用这个信息来解出x的值。我们知道4和x的最大公约数是2。这意味着x一定是2的倍数。所以，我们可以表示x为2乘以一个未知整数k：x = 2k其中k是任意整数。x可以是任意一个2的倍数。具体的数值取决于k的值。因此，无法确定x的具体数...
Doubtnut is the perfect NEET and IIT JEE preparation App. Get solutions for NEET and IIT JEE previous years papers, along with chapter wise NEET MCQ solutions. Get all the study material in Hindi medium and English medium for IIT JEE and NEET preparation ...
HCF of co-prime numbers 4 and 15 was found as follows by factorisation:4 = 2 × 2 and 15 =3 × 5 since there is no common prime factor, so HCF of 4 and 15 is 0.Is the answer correct? If not, what is the correct HCF?
The HCF of44x5y4,88x6y5, and66x7y6___. View Solution The HCF of4y4x−9y2x3and4y2x2+6yx3is View Solution Doubtnut is No.1 Study App and Learning App with Instant Video Solutions for NCERT Class 6, Class 7, Class 8, Class 9, Class 10, Class 11 and Class 12, IIT JEE prep...
Solved Question for You on HCF and LCM Question 1: The LCM and HCF of two numbers are 156 and 4 respectively. If one number is 52 find the other number. Answer :As it is given that the product of two numbers is equal to the product of HCF and LCM of two numbers. And HCF and ...
Mrs. Gomez needs to choose students from three sections with 12, 24, and 30 students to represent their sections for a school activity. She does not want to depend on how large or small the population of each section is. Rather, she wants to be fair by choosing the same or the common...
Step 4:For remainder = 0, divisor = 4 ⇒ HCF(4, 12) = 4 Thus, HCF(4, 8, 12) = HCF(HCF(4, 8), 12) = 4. HCF of 4, 8 and 12 by Prime Factorization Prime factorization of 4, 8 and 12 is (2 × 2), (2 × 2 × 2) and (2 × 2 × 3) respectively. As visible...